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Reaction of Alkenes with Cold & Hot KMnO4 | Chemca

Reaction of Alkenes with Cold & Hot KMnO4 | Chemca
Organic Chemistry

Oxidation of Alkenes with KMnO₄: Cold vs. Hot

By Chemca Editorial Team Last Updated: January 2026 9 min read

Potassium Permanganate ($KMnO_4$) behaves very differently with alkenes depending on the reaction conditions. With Cold, Dilute, Alkaline KMnO₄, it performs hydroxylation. However, with Hot, Concentrated, Acidic/Alkaline KMnO₄, it causes vigorous oxidative cleavage of the double bond.

1. Reaction with Cold Dilute Alkaline KMnO₄ (Baeyer's Reagent)

A 1% alkaline solution of cold potassium permanganate is known as Baeyer's Reagent. This reaction involves Syn-Hydroxylation (addition of two -OH groups to the same face) to form Vicinal Diols (Glycols).

$$ R-CH=CH-R + H_2O + [O] \xrightarrow{\text{Cold } KMnO_4} \underbrace{R-CH(OH)-CH(OH)-R}_{\text{Vicinal Diol (Glycol)}} $$

Test for Unsaturation

The purple color of $KMnO_4$ disappears, and a brown precipitate of Manganese Dioxide ($MnO_2$) forms. This color change (Purple $\to$ Colorless/Brown) is a classic laboratory test for the presence of double or triple bonds.

Mechanism & Stereochemistry

The reaction proceeds via a cyclic manganate ester intermediate.

  • The permanganate ion adds to the alkene face in a concerted manner, forming a five-membered cyclic ester.
  • Hydrolysis cleaves the Mn-O bonds, leaving two -OH groups on the same side of the plane.
  • Result: Syn-diol formation. Example: Cis-2-butene $\to$ Meso-2,3-butanediol.

2. Reaction with Hot Concentrated KMnO₄

Under vigorous conditions (Hot, Concentrated, usually Acidic), the carbon-carbon double bond is completely cleaved (broken). The fragments are oxidized to their highest oxidation states (Ketones or Carboxylic Acids).

$$ >C=C< \xrightarrow{\text{Hot } KMnO_4 / H^+} \text{Cleavage products (Ketones/Acids)} $$

Rules for Cleavage Products

The product depends on the substitution pattern of the alkene carbons:

  • Terminal $=CH_2$: Oxidizes to $CO_2 + H_2O$.
  • Monosubstituted $=CH-R$: Oxidizes to Carboxylic Acid ($R-COOH$).
  • Disubstituted $=CR_2$: Oxidizes to Ketone ($R-CO-R$). Ketones are resistant to further oxidation.

3. Examples of Oxidative Cleavage

A. 2-Butene

$$ CH_3-CH=CH-CH_3 \xrightarrow{\text{Hot } KMnO_4} 2 \ CH_3COOH \text{ (Acetic Acid)} $$

B. 2-Methyl-2-butene

Contains one disubstituted carbon and one monosubstituted carbon.

$$ (CH_3)_2C=CH-CH_3 \xrightarrow{\text{Hot } KMnO_4} \underbrace{(CH_3)_2C=O}_{\text{Acetone}} + \underbrace{CH_3COOH}_{\text{Acetic Acid}} $$

C. 1-Butene (Terminal Alkene)

$$ CH_3-CH_2-CH=CH_2 \xrightarrow{\text{Hot } KMnO_4} \underbrace{CH_3-CH_2-COOH}_{\text{Propanoic Acid}} + \underbrace{CO_2 + H_2O}_{\text{From } =CH_2} $$

4. Comparison: KMnO₄ vs Ozonolysis

Substrate Group Reductive Ozonolysis ($O_3, Zn$) Hot $KMnO_4$ / Oxidative Ozonolysis
$=CH-R$ Aldehyde ($R-CHO$) Carboxylic Acid ($R-COOH$)
$=CR_2$ Ketone ($R_2CO$) Ketone ($R_2CO$)
$=CH_2$ (Terminal) Formaldehyde ($HCHO$) $CO_2 + H_2O$

5. Oxidation of Cyclic Alkenes

Hot KMnO₄ opens the ring to form dicarboxylic acids or keto-acids.

Cyclohexene $\xrightarrow{\text{Hot } KMnO_4}$ Adipic Acid (Hexanedioic acid)
1-Methylcyclohexene $\xrightarrow{\text{Hot } KMnO_4}$ 6-Oxoheptanoic acid

KMnO4 Oxidation Quiz

Test your knowledge on Baeyer's reagent and Oxidative cleavage. 10 MCQs.

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