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Reaction with Ammonia Derivatives: Mechanism & Products | Chemca

Reaction with Ammonia Derivatives: Mechanism & Products | Chemca
Organic Chemistry

Reactions with Ammonia and its Derivatives

By Chemca Editorial Team Last Updated: January 2026 10 min read

Aldehydes and Ketones react with Ammonia ($NH_3$) and its derivatives ($NH_2-Z$) to form compounds containing a carbon-nitrogen double bond ($>C=N-Z$) with the elimination of a water molecule. This is a characteristic Nucleophilic Addition-Elimination reaction.

1. General Reaction

The general formula for ammonia derivatives is $H_2N-Z$, where $Z$ can be various groups like Alkyl, Hydroxyl, Amino, Phenyl, etc.

$$ >C=O + H_2N-Z \rightleftharpoons [\text{Intermediate}] \xrightarrow{-H_2O} >C=N-Z $$

Mechanism Summary:

  1. Addition: The nucleophilic nitrogen attacks the electrophilic carbonyl carbon. A proton transfers from nitrogen to oxygen to form a tetrahedral intermediate (carbinolamine).
  2. Elimination: The intermediate loses a molecule of water (acid-catalyzed dehydration) to form the $C=N$ double bond.

2. The Critical Role of pH

pH Control (Optimum pH $\approx$ 3.5)

The reaction requires a weak acid catalyst to protonate the carbonyl oxygen (making it more electrophilic) and to facilitate the elimination of water ($OH$ is a poor leaving group, $H_2O$ is good).

  • If pH is too low (Strongly Acidic): The amine ($NH_2-Z$) gets protonated to form an ammonium salt ($NH_3^+-Z$). Since it loses its lone pair, it is no longer nucleophilic and cannot attack the carbonyl.
  • If pH is too high (Basic): There is no protonation of the carbonyl oxygen or the -OH group, making the reaction extremely slow.

3. Specific Derivatives and Products

The table below summarizes the reagents and their corresponding products.

Reagent Name Formula ($NH_2-Z$) Product Name Product Structure
Hydroxylamine $NH_2-OH$ Oxime $>C=N-OH$
Hydrazine $NH_2-NH_2$ Hydrazone $>C=N-NH_2$
Phenylhydrazine $NH_2-NHPh$ Phenylhydrazone $>C=N-NHPh$
2,4-DNP $NH_2-NH-C_6H_3(NO_2)_2$ 2,4-DNP Hydrazone Orange/Red PPT
Semicarbazide $NH_2-NH-CO-NH_2$ Semicarbazone $>C=N-NH-CO-NH_2$
Primary Amine $R-NH_2$ Schiff's Base (Imine) $>C=N-R$

4. Key Exam Points

1. Semicarbazide Reaction Site

Semicarbazide has two $-NH_2$ groups. However, only one reacts.
The $NH_2$ attached directly to the carbonyl group ($CO$) is involved in resonance (amide-like), making its lone pair unavailable for nucleophilic attack.
Reaction occurs at the terminal $-NH_2$ group attached to the other nitrogen.

Active: $H_2N-\mathbf{NH}-CO-NH_2$ (Incorrect)
Correct Active Site: $\mathbf{H_2N}-NH-CO-NH_2$

2. Brady's Reagent (2,4-DNP)

2,4-Dinitrophenylhydrazine (2,4-DNP) is used to identify aldehydes and ketones. A positive test results in a Yellow, Orange, or Red precipitate of the 2,4-DNP hydrazone. This does not happen with carboxylic acids or esters.

5. Stereochemistry of Products

The formation of Oximes and Hydrazones creates a $C=N$ double bond. If the groups attached to the carbon are different ($R \neq R'$), Geometrical Isomerism (Syn/Anti) is possible.

Derivatives Quiz

Test your concepts on Carbonyl derivatives. 10 MCQs with explanations.

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