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Benzoin Condensation: Mechanism & Role of Cyanide | Chemca

Benzoin Condensation: Mechanism & Role of Cyanide | Chemca
Organic Chemistry

Benzoin Condensation: Formation of $\alpha$-Hydroxy Ketones

By Chemca Editorial Team Last Updated: January 2026 8 min read

The Benzoin Condensation is a coupling reaction between two molecules of aromatic aldehydes to form an $\alpha$-Hydroxy Ketone (also called an Acyloin). The reaction is typically catalyzed by cyanide ions ($CN^-$) or certain Thiamine (Vitamin B1) derivatives.

1. General Reaction

Two molecules of Benzaldehyde condense in the presence of alcoholic Potassium Cyanide ($KCN$) or Sodium Cyanide ($NaCN$) to form Benzoin.

$$ 2 C_6H_5CHO \xrightarrow{KCN (alc.), \ \Delta} \underbrace{C_6H_5-CH(OH)-CO-C_6H_5}_{\text{Benzoin}} $$

Conditions:

  • Substrate: Aromatic Aldehydes (Aliphatic aldehydes typically undergo Aldol condensation instead).
  • Reagent: Ethanolic KCN or NaCN.
  • Product: $\alpha$-Hydroxy Ketone.

2. The Unique Role of Cyanide

Why Cyanide?

The cyanide ion is a specific catalyst for this reaction because it fulfills three critical requirements:

  1. It is a strong nucleophile (attacks the carbonyl carbon).
  2. It is an electron-withdrawing group (stabilizes the intermediate carbanion).
  3. It is a good leaving group (leaves in the final step).

3. Detailed Mechanism

The reaction proceeds via the formation of a resonance-stabilized carbanion.

Step 1: Nucleophilic Attack

The cyanide ion ($CN^-$) attacks the carbonyl carbon of the first aldehyde molecule to form a cyanohydrin anion.

$$ Ph-CHO + CN^- \rightleftharpoons Ph-CH(O^-)-CN $$

Step 2: Proton Transfer (Carbanion Formation)

The proton on the carbon atom is acidic due to the electron-withdrawing nature of the adjacent Cyano group. A proton transfer occurs from Carbon to Oxygen, generating a stable carbanion.

$$ Ph-CH(O^-)-CN \rightleftharpoons Ph-C^-(OH)-CN $$

(This carbanion is stabilized by resonance with the CN group and the benzene ring).

Step 3: Nucleophilic Attack on Second Aldehyde

This stabilized carbanion attacks the carbonyl carbon of a second benzaldehyde molecule.

$$ Ph-C^-(OH)-CN + Ph-CHO \rightarrow Ph-C(OH)(CN)-CH(O^-)Ph $$

Step 4: Proton Transfer & Elimination of Cyanide

Rapid proton transfer occurs between the hydroxyl and alkoxide groups. Finally, the cyanide ion leaves to reform the carbonyl group, yielding Benzoin.

$$ \dots \xrightarrow{\text{Proton Transfer}} Ph-C(O^-)(CN)-CH(OH)Ph $$ $$ \xrightarrow{-CN^-} Ph-CO-CH(OH)Ph \text{ (Benzoin)} $$

4. Applications: Synthesis of Benzil

Benzoin can be oxidized by mild oxidizing agents (like Nitric Acid or Copper(II) Acetate) to form a diketone known as Benzil.

$$ Ph-CH(OH)-CO-Ph \xrightarrow{[O]} Ph-CO-CO-Ph \text{ (Benzil)} $$

5. Comparison with Aldol

Feature Aldol Condensation Benzoin Condensation
Reactants Aldehydes with $\alpha$-H Aromatic Aldehydes (No $\alpha$-H preferred)
Catalyst Dilute Base ($OH^-$) Cyanide Ion ($CN^-$)
Product $\beta$-Hydroxy Aldehyde $\alpha$-Hydroxy Ketone

Benzoin Condensation Quiz

Test your concepts on Cyanide catalysis. 10 MCQs with explanations.

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