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NaI in Acetone: The Finkelstein Reagent | Chemca

NaI in Acetone: The Finkelstein Reagent | Chemca
Organic Chemistry

NaI in Acetone: The Finkelstein Reaction

By Chemca Editorial Team Last Updated: January 2026 7 min read

The reagent combination of Sodium Iodide ($NaI$) dissolved in Dry Acetone is primarily used for the Finkelstein Reaction. This is a classic Halogen Exchange method used to convert Alkyl Chlorides or Bromides into Alkyl Iodides.

1. General Reaction

An alkyl halide ($R-X$, where $X = Cl, Br$) reacts with Sodium Iodide in Acetone to form an Alkyl Iodide and a sodium halide precipitate.

$$ R-X + NaI \xrightarrow{\text{Dry Acetone}} R-I + NaX \downarrow $$

Conditions:

  • Substrate: Alkyl Chloride ($R-Cl$) or Alkyl Bromide ($R-Br$).
  • Reagent: 15% solution of $NaI$ in anhydrous acetone.
  • Mechanism: $S_N2$ (Substitution Nucleophilic Bimolecular).

2. The Principle: Solubility Difference

Le Chatelier's Principle

The reaction is reversible. However, it is driven to completion by the precipitation of the byproduct.

Sodium Iodide ($NaI$) is soluble in Acetone (due to higher covalent character/polarization of Iodine).
Sodium Chloride ($NaCl$) and Sodium Bromide ($NaBr$) are insoluble in Acetone and precipitate out.

This removal of product ($NaX$) shifts the equilibrium towards the right.

3. Stereochemistry ($S_N2$)

The iodide ion ($I^-$) is a very good nucleophile and attacks the alkyl halide from the backside.

Outcome: Inversion of Configuration (Walden Inversion)

If optically active $(R)-2$-Chlorobutane reacts, the product will be $(S)-2$-Iodobutane.

4. Reactivity Order

Since it follows an $S_N2$ mechanism, the reactivity depends on steric hindrance.

  • Primary Halides ($1^\circ$): Most Reactive.
  • Secondary Halides ($2^\circ$): Moderate Reactivity.
  • Tertiary Halides ($3^\circ$): Unreactive (Steric hindrance prevents back-side attack; elimination may occur).
  • Aryl/Vinyl Halides: Do not react ($C-X$ bond is strong due to resonance).

5. Use as a Qualitative Test

The reagent can be used to distinguish alkyl bromides/chlorides from alkyl iodides or other non-reactive halides.

Observation

Positive Test: Formation of a white precipitate ($NaCl$ or $NaBr$) indicates the presence of Chlorine or Bromine.
Negative Test: No precipitate indicates Fluoride (too strong bond), Iodide (no reaction), or unreactive Aryl/Vinyl halides.

6. Summary Table

Reactant ($R-X$) Reagent Product Precipitate
$R-Cl$ $NaI$ / Acetone $R-I$ $NaCl \downarrow$
$R-Br$ $NaI$ / Acetone $R-I$ $NaBr \downarrow$
$R-F$ $NaI$ / Acetone No Reaction None

Finkelstein Quiz

Test your concepts on Halogen Exchange. 10 MCQs with explanations.

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