Chemistry: Full Syllabus Mock Test 4
Time: 3 Hours | Maximum Marks: 70
- The question paper is divided into four sections: A, B, C, and D.
- Section A: Q. No. 1 contains 10 multiple-choice questions carrying 1 mark each. Q. No. 2 contains 8 very short answer type questions carrying 1 mark each.
- Section B: Q. No. 3 to Q. No. 14 are short answer type questions carrying 2 marks each. Attempt any 8 questions.
- Section C: Q. No. 15 to Q. No. 26 are short answer type questions carrying 3 marks each. Attempt any 8 questions.
- Section D: Q. No. 27 to Q. No. 31 are long answer type questions carrying 4 marks each. Attempt any 3 questions.
- Use of logarithmic tables is allowed. Use of calculator is not allowed.
- Figures to the right indicate full marks.
SECTION A
Q1. Select and write the most appropriate answer from the given alternatives: [10 Marks]
-
Which of the following is an amorphous solid?
(A) Diamond(B) Glass(C) Sodium chloride(D) Graphite
-
The van't Hoff factor ($i$) for a dilute aqueous solution of Potassium sulfate ($K_2SO_4$) is approximately:
(A) 1(B) 2(C) 3(D) 4
-
Which of the following is an extensive property?
(A) Temperature(B) Density(C) Refractive index(D) Heat capacity
-
The SI unit of molar conductivity ($\Lambda_m$) is:
(A) $\text{S m}^{-1}$(B) $\text{S m}^2 \text{ mol}^{-1}$(C) $\text{S m}^2$(D) $\Omega^{-1} \text{ cm}^{-1}$
-
The molecularity of an elementary reaction $2A \rightarrow \text{Products}$ is:
(A) 0(B) 1(C) 2(D) 3
-
Which of the following Lanthanoids exhibits a +4 oxidation state?
(A) Cerium (Ce)(B) Europium (Eu)(C) Lutetium (Lu)(D) Promethium (Pm)
-
EDTA (Ethylenediaminetetraacetate) is an example of a:
(A) Unidentate ligand(B) Bidentate ligand(C) Tetradentate ligand(D) Hexadentate ligand
-
The best reagent for converting an alcohol into an alkyl chloride without separating by-products is:
(A) $HCl / ZnCl_2$(B) $PCl_3$(C) $PCl_5$(D) $SOCl_2$
-
The major product formed in the Reimer-Tiemann reaction of phenol is:
(A) Salicylic acid(B) Salicylaldehyde(C) Benzoquinone(D) Picric acid
-
The pyrimidine base present in DNA but absent in RNA is:
(A) Adenine(B) Guanine(C) Uracil(D) Thymine
Q2. Answer the following questions in one sentence: [8 Marks]
- Define: Boiling point of a liquid.
- What is a galvanic (voltaic) cell?
- Write the integrated rate law equation for a zero-order reaction.
- Write the chemical formula of chromyl chloride.
- What is a zwitterion?
- Name the monomer used in the preparation of Neoprene rubber.
- What is an ambidentate ligand?
- What is a chiral carbon atom?
SECTION B
Attempt any EIGHT of the following questions: [16 Marks]
- Distinguish between Isothermal process and Adiabatic process. (Any 2 points).
- State Henry's law. What is the effect of pressure on the solubility of a gas in a liquid?
- Calculate the spin-only magnetic moment of the $Fe^{2+}$ ion. (Atomic number of Fe = 26).
- Draw the chemical structures of $IF_7$ and $ClF_3$.
- Distinguish between a double salt and a coordination complex. (Any 2 points).
- Write a short note on the Wurtz-Fittig reaction with a chemical equation.
- Explain why phenol is acidic in nature.
- What is the action of bromine water on aniline at room temperature? Write the chemical equation.
- Distinguish between globular proteins and fibrous proteins. (Any 2 points).
- What is vulcanization of rubber? Why is it necessary?
- State any two principles of green chemistry.
- Write any two uses of Neon gas.
SECTION C
Attempt any EIGHT of the following questions: [24 Marks]
- Calculate the packing efficiency of a Body-Centered Cubic (BCC) unit cell.
- A solution containing 3.0 g of a non-volatile solute in 100 g of water boils at $100.26^\circ\text{C}$. Calculate the molar mass of the solute. ($K_b$ for water = 0.52 K kg/mol, Boiling point of pure water = $100^\circ\text{C}$).
- Derive the relationship between $\Delta H$ and $\Delta U$ for a chemical reaction involving gases.
- Calculate the standard EMF of the following cell at 298 K:
$Zn(s) | Zn^{2+}(0.1 \text{ M}) || Cu^{2+}(0.01 \text{ M}) | Cu(s)$
Given: $E^\circ_{Zn} = -0.76 \text{ V}$ and $E^\circ_{Cu} = +0.34 \text{ V}$. Use the Nernst equation to find the cell potential. - Derive the integrated rate law equation for a first-order reaction.
- Describe the preparation of Potassium Dichromate ($K_2Cr_2O_7$) from chromite ore. (Write only the necessary chemical equations).
- On the basis of Valence Bond Theory (VBT), explain the geometry and magnetic property of the $[CoF_6]^{3-}$ complex. (Atomic number of Co = 27).
- Describe the $S_N1$ mechanism for the alkaline hydrolysis of tert-butyl bromide.
- Explain the Williamson synthesis for the preparation of ethers with a suitable example.
- Write the chemical reactions for the preparation of ethylamine from:
- Nitroethane
- Acetonitrile
- Propionamide
- Explain the preparation of Bakelite. State its classification based on structure.
- Explain the Sol-Gel process for the synthesis of nanomaterials.
SECTION D
Attempt any THREE of the following questions: [12 Marks]
- (a) State Kohlrausch's law of independent migration of ions and write one of its applications. [2 Marks]
(b) Derive the relationship between standard cell potential ($E^\circ_{cell}$) and standard Gibbs free energy change ($\Delta G^\circ$). [2 Marks] - (a) Explain the Aldol condensation of acetaldehyde with a chemical equation. [3 Marks]
(b) What is a racemic mixture? [1 Mark] - (a) Derive the expression for the maximum work ($W_{max}$) done by a system during an isothermal and reversible expansion of an ideal gas. [3 Marks]
(b) What are copolymers? Give one example. [1 Mark] - (a) Describe the manufacture of Sulfuric acid ($H_2SO_4$) by the Contact process. (Write only the chemical equations). [3 Marks]
(b) Draw the structure of $XeF_6$. [1 Mark] - (a) Define half-life of a reaction. Show that for a first-order reaction, the half-life is independent of the initial concentration. [2 Marks]
(b) Calculate the effective atomic number (EAN) of Copper in $[Cu(NH_3)_4]^{2+}$. (Atomic number of Cu = 29). [2 Marks]
Solutions & Marking Scheme
Maximum Marks: 70
SECTION A [18 Marks]
Q1. Multiple Choice Answers [10 Marks]:
1. (B) Glass [1 M. The rest are crystalline solids]
2. (C) 3 [1 M. $K_2SO_4 \rightarrow 2K^+ + SO_4^{2-}$ (3 ions)]
3. (D) Heat capacity [1 M. It depends on the mass of the substance]
4. (B) $\text{S m}^2 \text{ mol}^{-1}$ [1 M]
5. (C) 2 [1 M. Two molecules of A are participating]
6. (A) Cerium (Ce) [1 M. Achieves stable $f^0$ configuration]
7. (D) Hexadentate ligand [1 M. 2 Nitrogen and 4 Oxygen donor sites]
8. (D) $SOCl_2$ [1 M. Darzen's method gives gaseous byproducts]
9. (B) Salicylaldehyde [1 M]
10. (D) Thymine [1 M. RNA contains Uracil instead]
Q2. Very Short Answers [8 Marks]:
1. Boiling point: The temperature at which the vapor pressure of a liquid becomes equal to the external atmospheric pressure. [1 M]
2. Galvanic cell: An electrochemical cell that converts the chemical energy of a spontaneous redox reaction into electrical energy. [1 M]
3. Zero-order integrated rate law: $k = \frac{[A]_0 - [A]_t}{t}$. [1 M]
4. Chromyl chloride formula: $CrO_2Cl_2$. [1 M]
5. Zwitterion: A dipolar, electrically neutral ion formed by internal proton transfer from a carboxyl group to an amino group within an amino acid. [1 M]
6. Monomer of Neoprene: Chloroprene (2-chloro-1,3-butadiene). [1 M]
7. Ambidentate ligand: A unidentate ligand containing two different donor atoms but coordinating through only one of them at a time (e.g., $NO_2^-$). [1 M]
8. Chiral carbon atom: A carbon atom that is bonded to four different atoms or groups of atoms. [1 M]
SECTION B [16 Marks] (Attempt Any 8)
Q3. Isothermal vs Adiabatic Process:
| Isothermal Process | Adiabatic Process |
|---|---|
| Temperature of the system remains constant ($\Delta T = 0$). | Temperature of the system changes ($\Delta T \neq 0$). |
| Heat is exchanged with surroundings ($q \neq 0$). | No heat is exchanged with surroundings ($q = 0$). |
[1 M for each point. Total 2 M]
Q4. Henry's Law & Pressure Effect:
Statement: The solubility of a gas in a liquid at a constant temperature is directly proportional to the partial pressure of the gas above the solution. [1 M]
Effect of Pressure: As pressure increases, the solubility of the gas in the liquid increases. [1 M]
Q5. Magnetic Moment of $Fe^{2+}$:
Electronic configuration of Fe (Z=26) is $[Ar] 3d^6 4s^2$. $Fe^{2+}$ is $[Ar] 3d^6$. [1/2 M]
In $3d^6$, there are 4 unpaired electrons ($n=4$). [1/2 M]
$\mu = \sqrt{n(n+2)} = \sqrt{4(6)} = \sqrt{24} \approx 4.90 \text{ B.M.}$ [1 M]
Q6. Structures of $IF_7$ and $ClF_3$:
$IF_7$: Pentagonal bipyramidal. (Central I, 5 F's in a pentagon, 2 axial). [1 M for drawing/description]
$ClF_3$: T-shaped. (Central Cl, 3 F's, 2 lone pairs on equatorial positions). [1 M for drawing/description]
Q7. Double Salt vs Coordination Complex:
- Double salts dissociate completely into simple ions in water; Coordination complexes do not dissociate completely (complex ion remains intact).
- Double salts lose their solid-state identity in solution; Coordination complexes retain their identity in solution.
[1 M for each point. Total 2 M]
Q8. Wurtz-Fittig Reaction:
A mixture of an alkyl halide and an aryl halide reacts with sodium metal in dry ether to form an alkylbenzene. [1 M]
$C_6H_5-Br + 2Na + Br-CH_3 \xrightarrow{\text{Dry Ether}} C_6H_5-CH_3 \text{ (Toluene)} + 2NaBr$ [1 M]
Q9. Acidic nature of Phenol:
Phenol is acidic because the O-H bond weakens due to electron withdrawal by the benzene ring. After losing a proton, the resulting phenoxide ion is highly stabilized by resonance, which shifts the equilibrium forward. [2 M]
Q10. Bromine water on Aniline:
Aniline reacts rapidly to form a white precipitate of 2,4,6-tribromoaniline. [1 M]
$C_6H_5NH_2 + 3Br_2(aq) \rightarrow C_6H_2Br_3NH_2 \downarrow + 3HBr$ [1 M]
Q11. Globular vs Fibrous Proteins:
- Globular: Polypeptides fold into spherical shapes; Fibrous: Polypeptides form parallel thread-like structures.
- Globular: Soluble in water (e.g., Insulin); Fibrous: Insoluble in water (e.g., Keratin).
[1 M for each point. Total 2 M]
Q12. Vulcanization of Rubber:
The process of heating natural rubber with sulfur (3-5%) to form 3D cross-links between polymer chains. [1 M]
Necessity: Natural rubber is soft, sticky, and has low tensile strength. Vulcanization makes it hard, non-sticky, and highly elastic. [1 M]
Q13. Principles of Green Chemistry (Any 2):
- Prevention of Waste: Prevent waste rather than treating it after formation.
- Atom Economy: Maximize incorporation of reactants into final products.
- Catalysis: Use catalysts to reduce energy and waste.
[1 M for each point. Total 2 M]
Q14. Uses of Neon gas:
- Used in discharge tubes and fluorescent bulbs for advertisement display (neon signs). [1 M]
- Used in voltage regulators and indicators. [1 M]
SECTION C [24 Marks] (Attempt Any 8)
Q15. Packing Efficiency of BCC:
In BCC, atoms touch along the body diagonal. $4r = \sqrt{3}a \implies a = \frac{4r}{\sqrt{3}}$. [1 M]
Volume of unit cell $V = a^3 = \frac{64r^3}{3\sqrt{3}}$. [1/2 M]
Volume of 2 atoms in BCC $= 2 \times \frac{4}{3}\pi r^3 = \frac{8}{3}\pi r^3$. [1/2 M]
P.E. $= \frac{\frac{8}{3}\pi r^3}{\frac{64r^3}{3\sqrt{3}}} \times 100 = \frac{\sqrt{3}\pi}{8} \times 100 \approx 68\%$. [1 M]
Q16. Molar Mass from Elevation in BP:
Given: $W_2 = 3.0\text{g}, W_1 = 100\text{g}, K_b = 0.52$. $\Delta T_b = 100.26 - 100 = 0.26\text{K}$. [1 M]
Formula: $M_2 = \frac{1000 \cdot K_b \cdot W_2}{\Delta T_b \cdot W_1}$ [1/2 M]
Calc: $M_2 = \frac{1000 \times 0.52 \times 3.0}{0.26 \times 100} = \frac{1560}{26}$ [1 M]
$M_2 = 60 \text{ g/mol}$. [1/2 M]
Q17. $\Delta H$ and $\Delta U$ Derivation:
Enthalpy $H = U + PV$. For a change at constant pressure, $\Delta H = \Delta U + P\Delta V = \Delta U + P(V_2 - V_1)$. [1 M]
Using ideal gas law for reactants/products: $PV_1 = n_1RT$ and $PV_2 = n_2RT$. [1 M]
$\Delta H = \Delta U + n_2RT - n_1RT \implies \Delta H = \Delta U + \Delta n_g RT$. [1 M]
Q18. Nernst Equation EMF Calculation:
1. $E^\circ_{cell} = 0.34 - (-0.76) = 1.10 \text{ V}$. $n = 2$. [1 M]
2. $E_{cell} = 1.10 - \frac{0.0592}{2} \log_{10}\left(\frac{[Zn^{2+}]}{[Cu^{2+}]}\right) = 1.10 - 0.0296 \log_{10}\left(\frac{0.1}{0.01}\right)$ [1 M]
3. $E_{cell} = 1.10 - 0.0296 \log_{10}(10) = 1.10 - 0.0296 = 1.0704 \text{ V}$. [1 M]
Q19. First-Order Integrated Rate Law:
Rate $= -\frac{d[A]}{dt} = k[A] \implies \frac{d[A]}{[A]} = -k \cdot dt$. [1 M]
Integrate from $[A]_0$ to $[A]_t$: $\ln[A]_t - \ln[A]_0 = -kt$. [1 M]
Convert to log10: $k = \frac{2.303}{t} \log_{10} \frac{[A]_0}{[A]_t}$. [1 M]
Q20. Preparation of $K_2Cr_2O_7$ from Chromite:
1. $4FeCr_2O_4 + 8Na_2CO_3 + 7O_2 \rightarrow 8Na_2CrO_4 + 2Fe_2O_3 + 8CO_2$ [1 M]
2. $2Na_2CrO_4 + H_2SO_4 \rightarrow Na_2Cr_2O_7 + Na_2SO_4 + H_2O$ [1 M]
3. $Na_2Cr_2O_7 + 2KCl \rightarrow K_2Cr_2O_7 \downarrow + 2NaCl$ [1 M]
Q21. VBT for $[CoF_6]^{3-}$:
$Co^{3+}$ is $3d^6$. $F^-$ is a weak field ligand, does not pair the 4 unpaired electrons. [1 M]
Uses outer orbitals (one 4s, three 4p, two 4d) $\rightarrow$ $sp^3d^2$ hybridization $\rightarrow$ Octahedral. [1 M]
Because of 4 unpaired electrons, it is strongly Paramagnetic. [1 M]
Q22. $S_N1$ Mechanism:
Two-step process. Rate $= k[(CH_3)_3C-Br]$. [1 M]
Step 1 (Slow): Cleavage forms planar tertiary carbocation $(CH_3)_3C^+$. [1 M]
Step 2 (Fast): $OH^-$ attacks from front or back, leading to a Racemic mixture. [1 M]
Q23. Williamson Synthesis:
Reaction of alkyl halide with sodium alkoxide to form ethers via $S_N2$ mechanism. [1.5 M]
$C_2H_5-Br + CH_3-O^-Na^+ \rightarrow C_2H_5-O-CH_3 + NaBr$ [1.5 M]
Q24. Preparation of Ethylamine:
1. $CH_3CH_2NO_2 + 6[H] \xrightarrow{Sn/HCl} CH_3CH_2NH_2 + 2H_2O$ [1 M]
2. $CH_3CN + 4[H] \xrightarrow{Na/C_2H_5OH} CH_3CH_2NH_2$ [1 M]
3. $CH_3CH_2CONH_2 + Br_2 + 4NaOH \xrightarrow{\Delta} CH_3CH_2NH_2 + Na_2CO_3 + 2NaBr + 2H_2O$ [1 M]
Q25. Preparation of Bakelite:
Phenol + Formaldehyde $\rightarrow$ Novolac (linear polymer). [1 M]
Novolac + hexamethylenetetramine $\xrightarrow{\Delta}$ Bakelite (3D cross-linked solid). [1 M]
Classification: Cross-linked / Network polymer. [1 M]
Q26. Sol-Gel Process:
- Hydrolysis: Precursors form a colloidal solution (Sol). [1 M]
- Polycondensation: Particles link to form a 3D network enclosing liquid (Gel). [1 M]
- Calcination: Dried gel heated to form final nanomaterial. [1 M]
SECTION D [12 Marks] (Attempt Any 3)
Q27. (a) Kohlrausch's law [2 Marks] (b) $\Delta G^\circ$ Derivation [2 Marks]
(a) At infinite dilution, each ion migrates independently and makes its own definite contribution to total molar conductivity. [1 M]
Application: Used to calculate molar conductivity of weak electrolytes at infinite dilution. [1 M]
(b) Max electrical work = Decrease in Gibbs Free Energy: $-\Delta G^\circ = W_{elec}$. [1 M]
Electrical work = Charge $\times$ Potential = $nF \times E^\circ_{cell}$. Therefore, $\Delta G^\circ = -nFE^\circ_{cell}$. [1 M]
Q28. (a) Aldol Condensation [3 Marks] (b) Racemic Mixture [1 Mark]
(a) Two molecules of acetaldehyde (with $\alpha$-H) condense in dil. NaOH to form Acetaldol. [1 M]
$2CH_3CHO \xrightarrow{\text{dil. NaOH}} CH_3CH(OH)CH_2CHO$ [1 M]
On heating, loses water: $CH_3CH(OH)CH_2CHO \xrightarrow{\Delta, -H_2O} CH_3CH=CHCHO$ (Crotonaldehyde). [1 M]
(b) An equimolar mixture of two enantiomers which is optically inactive. [1 M]
Q29. (a) $W_{max}$ Derivation [3 Marks] (b) Copolymers [1 Mark]
(a) $dW = -P_{ex} dV$. For reversible, $P_{ex} \approx P$. So $dW = -P dV$. [1 M]
$W_{max} = -\int_{V_1}^{V_2} P \, dV = -\int_{V_1}^{V_2} \frac{nRT}{V} dV$. [1 M]
$W_{max} = -nRT \ln(V_2/V_1) = -2.303 nRT \log_{10}(V_2/V_1)$. [1 M]
(b) Polymers made from two or more different monomers (e.g., Buna-S). [1 M]
Q30. (a) Contact Process Equations [3 Marks] (b) $XeF_6$ Structure [1 Mark]
(a) 1. $S_8(s) + 8O_2(g) \rightarrow 8SO_2(g)$ [1 M]
2. $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$ ($V_2O_5$) [1 M]
3. $SO_3(g) + H_2SO_4(l) \rightarrow H_2S_2O_7(l) \xrightarrow{H_2O} 2H_2SO_4(aq)$ [1 M]
(b) Distorted octahedral. (Draw hexagon with Xe in center, 6 Fs, 1 lone pair protruding). [1 M]
Q31. (a) Half-life Independence [2 Marks] (b) EAN of Cu [2 Marks]
(a) Half-life is the time for concentration to reduce to half. For first order, $t_{1/2} = \frac{0.693}{k}$. [1 M]
Since $[A]_0$ does not appear in this equation, $t_{1/2}$ is independent of initial concentration. [1 M]
(b) In $[Cu(NH_3)_4]^{2+}$, Z = 29. Oxidation state of Cu (X) = +2. [1 M]
Electrons from 4 $NH_3$ (Y) = $4 \times 2 = 8$. EAN = $29 - 2 + 8 = 35$. [1 M]
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