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Chemistry Bridge Course Lecture 14

Chemistry Bridge Course - Lecture 14 | CHEMCA JEE & NEET
CHEMCA
Lecture 14 Organic Chemistry Target: Class 10 to 11 Transition (JEE/NEET)

Nomenclature of Alkenes, Alkynes & Functional Groups

Welcome to Lecture 14 of the CHEMCA Bridge Course! After mastering alkanes, we now step into unsaturated systems and functional groups. In this session, Abhishek Sengar Sir details parent chain selections with multiple bonds, alphabetical tie-breakers between double and triple bonds, and the IUPAC functional group seniority hierarchy.

Video Lecture Broadcast

Instructor: Abhishek Sengar Sir Published: April 30, 2026 Subject: Unsaturated & Functional IUPAC

Interactive Lecture Timestamps

Click any topic to skip the video directly to that specific concept explanation.

In-Depth Lecture Notes & Summary

01

Nomenclature of Alkenes & Alkynes

Unsaturated hydrocarbons contain carbon-carbon double bonds ($\text{C}=\text{C}$) or triple bonds ($\text{C}\equiv\text{C}$). Their naming follows specific adjustments to standard alkane rules:

1. Parent Chain Selection: The selected parent carbon chain must contain the maximum number of multiple bonds, even if it is not the longest continuous carbon chain in the molecule.

2. Numbering Priority: Number the parent chain from the end that gives the lowest possible locant to multiple bonds. Substituents (alkyl groups, halogens) are given lower priority during numbering compared to double/triple bonds.

Double vs. Triple Bond Tie-Breaker Rule

If a double bond and a triple bond are present at symmetrical positions from both ends of the parent chain, the double bond is given lower locant numbering priority due to alphabetical ordering ("ene" comes before "yne"):
$\text{HC}\equiv\text{C}-\text{CH}_2-\text{CH}=\text{CH}_2 \implies \text{Pent-1-en-4-yne}$ (Not Pent-4-en-1-yne)

02

Functional Group Seniority Hierarchy

When a compound contains more than one chemical functional group, one group is designated as the **Principal Functional Group** (written as the secondary suffix) based on IUPAC seniority. All other remaining functional groups are treated as **Substituents** (written as prefixes).

Decreasing Priority Order:
$-\text{COOH} > -\text{SO}_3\text{H} > -\text{COOR} > -\text{COCl} > -\text{CONH}_2 > -\text{CN} > -\text{CHO} > \text{C}=\text{O} > -\text{OH} > -\text{NH}_2 > \text{C}=\text{C} \ge \text{C}\equiv\text{C}$

Seniority Group Explorer

Click any functional group in the dropdown list (arranged in exact descending seniority) to inspect its IUPAC prefix, suffix, and structural properties.

Group Properties: -COOH

Principal Suffix: -oic acid
Substituent Prefix: carboxy-
Solved IUPAC Example

Ethanoic acid

CH₃-COOH

Lecture 14 Concept Test

Validate your understanding of unsaturated numbering and priority ties.

Question 1 of 5

Score: 0/0

Confused by Priority Ties?

If you are struggling with the alphabetical priority rules or choosing suffixes in polyfunctional compounds, email Abhishek Sir directly!

Email Support →

Solved Unsaturated & Functional Naming Gallery

Select any of the 5 organic compounds discussed in class to display its chemical structure, formula, and complete IUPAC nomenclature proof.

Alkene

Pent-2-ene

Condensed: CH₃-CH=CH-CH₂-CH₃

Explanation goes here...
Root: pent Pri. Suffix: ene Sec. Suffix: None Prefix: None

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1 comment:

  1. Anonymous17:32

    A very high-quality explanation.

    ReplyDelete

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