CHEMCA
EXAM MASTER REVIEW SHEET
Organic Chemistry: Carboxylic Acids
1 Structure & Physical Properties
Carboxylic acids ($R-COOH$) consist of a carbonyl group attached to a hydroxyl group. The carboxyl carbon is $sp^2$ hybridized.
Carboxylic acids have higher boiling points than aldehydes, ketones, and even alcohols of comparable molecular masses.
- This is due to extensive intermolecular hydrogen bonding.
- Most carboxylic acids exist as cyclic dimers in the vapor phase or in aprotic solvents (like benzene).
Simple aliphatic carboxylic acids up to 4 carbon atoms are miscible in water due to the formation of hydrogen bonds with water.
Solubility rapidly decreases as the number of carbon atoms increases (the hydrophobic alkyl chain dominates).
2 Acidity & Electronic Effects
Carboxylic acids are more acidic than phenols because the carboxylate ion ($R-COO^-$) is stabilized by two equivalent resonance structures (negative charge is delocalized over two highly electronegative oxygen atoms), whereas the phenoxide ion has non-equivalent structures with negative charge on less electronegative carbons.
Electron Withdrawing Groups (-I, -M)
EWGs increase acidity by stabilizing the conjugate base via delocalization of negative charge.
$CF_3COOH > CCl_3COOH > CHCl_2COOH > CH_2ClCOOH > HCOOH > CH_3COOH$
Electron Releasing Groups (+I, +M)
ERGs decrease acidity by destabilizing the conjugate base (intensifying negative charge).
$HCOOH > CH_3COOH > CH_3CH_2COOH$
3 Key Preparation Methods
Oxidation Reactions
From $1^\circ$ Alcohols / Aldehydes using strong oxidants ($KMnO_4, K_2Cr_2O_7$, Jones reagent).
From Alkylbenzenes: Entire side chain is oxidized to $-COOH$ regardless of length, provided there is at least one benzylic hydrogen.
Hydrolysis & Grignard
From Nitriles ($R-CN$): Acidic or basic hydrolysis yields amides, then acids.
From Grignard Reagent: Excellent for ascending the series (adding 1 Carbon).
4 Chemical Reactions
| Reaction Type / Cleavage | Reagents | Product & Key Notes |
|---|---|---|
| Reaction with Metals/Alkalies (Cleavage of O-H bond) |
$Na, NaOH, NaHCO_3$ |
Forms carboxylate salts. $NaHCO_3$ Test: Produces brisk effervescence of $CO_2$. Used to distinguish acids from phenols (most phenols don't react). |
| Anhydride Formation (Cleavage of C-OH bond) |
$H_2SO_4 / \Delta$ or $P_2O_5 / \Delta$ | Dehydration of two acid molecules yields an Acid Anhydride ($(RCO)_2O$). |
| Fischer Esterification | $R'-OH + \text{Conc. } H_2SO_4$ | Reversible reaction yielding Esters (Fruity smell). The $-OH$ comes from the acid and the $-H$ from the alcohol. |
| Formation of Acid Chlorides | $PCl_5, PCl_3$ or $SOCl_2$ | Yields $R-COCl$. Thionyl chloride ($SOCl_2$) is preferred because the byproducts ($SO_2, HCl$) are gases and easily escape. |
| Reaction with Ammonia | $NH_3$, followed by heat ($\Delta$) | Forms ammonium salt first, which on intense heating loses water to form an Amide ($R-CONH_2$). |
5 Decarboxylation, Reduction & Substitution
Reductions & Decarboxylation
Uses $LiAlH_4$ / ether or $B_2H_6$. Important: $NaBH_4$ does NOT reduce carboxyl groups.
$R-COOH \xrightarrow{(i) LiAlH_4, \text{ ether } (ii) H_3O^+} R-CH_2OH$
Heating Na/K salts with Soda-Lime ($NaOH + CaO$, 3:1) removes $CO_2$ yielding alkanes with one less carbon.
$R-COONa \xrightarrow{NaOH+CaO, \Delta} R-H + Na_2CO_3$
Electrolysis of aqueous solution of Na/K salts yields alkanes (at Anode) with even number of carbons.
$2R-COONa \xrightarrow{\text{Electrolysis}} R-R + 2CO_2 + ...$
Hell-Volhard-Zelinsky (HVZ)
Halogenation of aliphatic acids at the $\alpha$-position. Requires at least one $\alpha$-hydrogen.
$R-CH_2-COOH \xrightarrow{\text{(i) } X_2 / \text{Red P} \text{ (ii) } H_2O} R-CH(X)-COOH$
$X = Cl, Br$
Electrophilic Aromatic Substitution
The $-COOH$ group is strongly Deactivating and Meta-Directing.
JEE Trap: Benzoic acid does NOT undergo Friedel-Crafts alkylation or acylation because the carboxyl group strongly deactivates the ring and binds with the Lewis acid catalyst ($AlCl_3$).
- Nitration: Gives m-Nitrobenzoic acid.
- Bromination: Gives m-Bromobenzoic acid (using $Br_2/FeBr_3$).
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