CHEMCA
EXAM MASTER REVIEW SHEET
Organic Chemistry: Aldehydes & Ketones
1 Carbonyl Group: Structure & Reactivity
The carbonyl carbon is $sp^2$ hybridized. The $>C=O$ bond is highly polarized due to higher electronegativity of oxygen, making the carbon electrophilic.
Aldehydes are generally more reactive than ketones towards Nucleophilic Addition ($N_A$) due to:
- Steric Hindrance: Ketones have two bulky alkyl groups that hinder the approach of a nucleophile to the carbonyl carbon.
- Electronic Factor (+I effect): Two alkyl groups in ketones release electrons (+I), reducing the electrophilicity (positive charge) on the carbonyl carbon more than one alkyl group in aldehydes.
Aliphatic > Aromatic (due to +R effect of benzene ring)
Boiling Point: Higher than hydrocarbons and ethers of comparable mass (due to weak dipole-dipole interactions), but lower than alcohols (absence of intermolecular H-bonding).
Solubility: Lower aldehydes and ketones (up to 4 carbons) are miscible with water because they form H-bonds with water. Solubility drops rapidly with increasing alkyl chain size.
2 Key Preparation Methods
Rosenmund Reduction
Aldehydes OnlyCatalytic hydrogenation of acid chlorides. Barium sulfate acts as a catalytic poison to stop further reduction to alcohol.
Stephen Reaction
Aldehydes OnlyReduction of nitriles with stannous chloride and HCl, followed by hydrolysis of the intermediate imine.
Etard Reaction
BenzaldehydeOxidation of toluene using chromyl chloride ($CrO_2Cl_2$). Forms a brown chromium complex which hydrolyzes to benzaldehyde.
Ozonolysis of Alkenes
Ald/KetReductive cleavage of $C=C$ double bonds using ozone followed by Zinc dust and water.
3 Nucleophilic Addition Reactions
The planar carbonyl carbon is attacked by a nucleophile from above or below, changing hybridization from $sp^2$ to $sp^3$ (tetrahedral intermediate).
| Reagent / Nucleophile | Product Formed | Mechanism / Key Observation |
|---|---|---|
| Hydrogen Cyanide ($HCN$) | Cyanohydrin | Base-catalyzed reaction (base generates the strong $CN^-$ nucleophile). Useful for ascending the carbon chain. |
| Sodium Bisulphite ($NaHSO_3$) | Bisulphite Addition Compound | Forms a white crystalline precipitate. Used for separation and purification of aldehydes (and sterically unhindered ketones). |
| Grignard Reagent ($RMgX$) | Alcohols |
$HCHO \rightarrow 1^\circ$ Alcohol Other Aldehydes $\rightarrow 2^\circ$ Alcohol Ketones $\rightarrow 3^\circ$ Alcohol |
| Alcohols ($ROH / H^+$) | Acetals & Ketals | Aldehydes form hemiacetals then acetals. Ketones form cyclic ketals with ethylene glycol (used as a protecting group in organic synthesis). |
| Ammonia Derivatives ($NH_2-Z$) | Imines / Hydrazones / Oximes | Requires strict pH control (~3.5). 2,4-DNP test (Brady's reagent) yields an Orange/Yellow/Red precipitate, confirming presence of carbonyl group. |
4 Reactions of $\alpha$-Hydrogen
Requirement: Must have at least one $\alpha$-Hydrogen atom.
Reagent: Dilute alkali ($dil. NaOH$, $Ba(OH)_2$).
Two molecules condense to form a $\beta$-hydroxy aldehyde (Aldol) or ketone (Ketol). Upon heating, they readily dehydrate to form $\alpha,\beta$-unsaturated carbonyl compounds.
Requirement: Aldehydes with NO $\alpha$-Hydrogen atoms ($HCHO$, $PhCHO$).
Reagent: Concentrated alkali ($50\% \ NaOH$ or $KOH$).
A disproportionation (self-oxidation-reduction) reaction. One molecule is oxidized to carboxylic acid salt, the other is reduced to an alcohol.
5 Distinguishing Tests & Reductions
Reduction to Hydrocarbons (Alkanes)
Uses Zinc amalgam and concentrated HCl.
$>C=O \xrightarrow{Zn-Hg / \text{Conc. } HCl} >CH_2 + H_2O$
Uses Hydrazine followed by heating with KOH/Glycol.
$>C=O \xrightarrow{NH_2NH_2} \text{Hydrazone} \xrightarrow{KOH / \text{Glycol}, \Delta} >CH_2 + N_2$
Chemical Tests (Lab Identification)
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Tollens' Test (Silver Mirror Test)
Reagent: Ammoniacal Silver Nitrate. Only Aldehydes (both aliphatic & aromatic) reduce Tollens' reagent to a bright silver mirror. Ketones fail.
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Fehling's Test
Reagent: Fehling A (aq. $CuSO_4$) + Fehling B (Rochelle salt). Only Aliphatic Aldehydes give a reddish-brown ppt of $Cu_2O$. Aromatic aldehydes (Benzaldehyde) and ketones fail.
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Haloform (Iodoform) Test
Reagent: $NaOI$ (or $NaOH + I_2$). Compounds with a methyl ketone group ($CH_3-CO-$) or those oxidized to it ($CH_3-CH(OH)-$) give a yellow ppt of Iodoform ($CHI_3$).
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