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Sulfuric Acid (H2SO4): Contact Process & Properties

Sulfuric Acid (H2SO4): Contact Process & Properties | chemca
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Inorganic Chemistry • Group 16 Compounds

Sulfuric Acid ($H_2SO_4$)

The Contact Process, Oleum, and the Three Pillars of Reactivity.

By chemca Team • Updated Sep 2026

Sulfuric acid is often called the "King of Chemicals" because a nation's industrial strength can literally be measured by the quantity of sulfuric acid it produces and consumes. It is an incredibly dense, oily liquid that serves as a strong acid, a powerful dehydrating agent, and an oxidizing agent. Let's master its industrial manufacture and its highly tested chemical reactions.

1. Manufacture: The Contact Process

The modern industrial production of sulfuric acid occurs via the Contact Process, which involves three fundamental steps.

Step 1: Production of Sulfur Dioxide ($SO_2$)

Sulfur or sulfide ores (like iron pyrites) are burned/roasted in excess air to produce sulfur dioxide gas.

$S_8 + 8O_2 \xrightarrow{\Delta} 8SO_2$

Step 2: Catalytic Oxidation to Sulfur Trioxide ($SO_3$)

This is the crucial, rate-determining step. The $SO_2$ is mixed with more oxygen and passed over a Vanadium Pentoxide ($V_2O_5$) catalyst to form $SO_3$.

$2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g) \quad \Delta H^\ominus = -196.6 \text{ kJ mol}^{-1}$

According to Le Chatelier's Principle, because the reaction is exothermic and decreases volume (3 moles $\rightarrow$ 2 moles), maximum yield requires Low Temperature (~720 K) and High Pressure (~2 bar).

Step 3: Absorption & The Oleum Trap

You might think the next logical step is to just dissolve the $SO_3$ in water ($SO_3 + H_2O \rightarrow H_2SO_4$). This is a massive exam trap!

⚠️ Why don't we add $SO_3$ directly to water?
The reaction is incredibly violent and highly exothermic. It forms a dense, dangerous fog of sulfuric acid droplets that does not condense easily.

Instead, $SO_3$ is absorbed into Concentrated Sulfuric Acid ($H_2SO_4$) to form Oleum (fuming sulfuric acid, $H_2S_2O_7$). The Oleum is then safely diluted with water to get the desired concentration of $H_2SO_4$.

$SO_3 + H_2SO_4 \rightarrow \mathbf{H_2S_2O_7} \text{ (Oleum)}$

$H_2S_2O_7 + H_2O \rightarrow 2H_2SO_4$
Flowchart: The Contact Process Sulfur Burner S + O₂ ➔ SO₂ SO₂ + O₂ Catalytic Converter (V₂O₅ Catalyst) ➔ SO₃ SO₃ gas Absorption Tower Absorb in Conc. H₂SO₄ ➔ Oleum + H₂O Dilution H₂SO₄ (98% pure) The key safety step is forming Oleum (H₂S₂O⇇) to avoid the explosive direct reaction of SO₃ with water.

2. Properties & The Dibasic Nature

Pure sulfuric acid is a colorless, dense, oily liquid. It is highly soluble in water with the evolution of a massive amount of heat. It is a strong dibasic acid, meaning it ionizes in two steps in aqueous solution.

Step 1: $H_2SO_4(aq) + H_2O(l) \rightarrow H_3O^+(aq) + HSO_4^-(aq) \quad (K_{a1} > 10)$

Step 2: $HSO_4^-(aq) + H_2O(l) \rightleftharpoons H_3O^+(aq) + SO_4^{2-}(aq) \quad (K_{a2} = 1.2 \times 10^{-2})$
Why is $K_{a1} \gg K_{a2}$?
The first dissociation is almost complete (it is a very strong acid). However, the second dissociation is much harder because it requires removing a positively charged proton ($H^+$) from an ion that is already negatively charged ($HSO_4^-$). This electrostatic attraction severely hinders the second ionization.

3. Chemical Reactions: The Three Pillars

For competitive exams, almost all reactions of concentrated sulfuric acid fall into one of three distinct categories based on its unique chemical properties.

A. Low Volatility

Concentrated $H_2SO_4$ has a very high boiling point ($590\text{ K}$) due to extensive hydrogen bonding. Because it is non-volatile, it is used to manufacture more volatile acids (like $HCl$, $HNO_3$, and $HF$) from their corresponding metal salts.

$2NaCl + H_2SO_4 \xrightarrow{\Delta} \mathbf{2HCl \uparrow} + Na_2SO_4$

$KNO_3 + H_2SO_4 \xrightarrow{\Delta} \mathbf{HNO_3 \uparrow} + KHSO_4$

B. Strong Dehydrating Agent

Concentrated sulfuric acid has a tremendous affinity for water. It will strip the elements of water (H and O) out of organic compounds. The most famous example is the Charring of Carbohydrates (like cane sugar).

$C_{12}H_{22}O_{11} \xrightarrow{\text{Conc. } H_2SO_4} \mathbf{12C \text{ (Black Carbon)}} + 11H_2O$

It also dehydrates Formic Acid ($HCOOH$) into Carbon Monoxide gas:
$HCOOH \xrightarrow{H_2SO_4} \mathbf{CO \uparrow} + H_2O$

C. Moderately Strong Oxidizing Agent

Hot concentrated sulfuric acid is a moderately strong oxidizing agent (intermediate between $HNO_3$ and $H_3PO_4$). In redox reactions, it is itself reduced exclusively to Sulfur Dioxide ($SO_2$) gas.

1. Oxidizing Metals (e.g., Copper):

Unlike dilute acids which release $H_2$ gas, concentrated $H_2SO_4$ oxidizes the metal and releases $SO_2$.

$Cu(s) + 2H_2SO_4(\text{conc.}) \rightarrow CuSO_4(aq) + \mathbf{SO_2(g)} \uparrow + 2H_2O(l)$
2. Oxidizing Non-Metals (e.g., Carbon & Sulfur):
$C + 2H_2SO_4(\text{conc.}) \rightarrow CO_2(g) + \mathbf{2SO_2(g)} \uparrow + 2H_2O(l)$

$S_8 + 16H_2SO_4(\text{conc.}) \rightarrow \mathbf{24SO_2(g)} \uparrow + 16H_2O(l)$

Mastery Check: Sulfuric Acid

15 High-Yield Questions to test your JEE/NEET Preparation

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