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NEET Crash Course Module - 89

Reactions of Amines & Diazonium Salts: NEET Crash Course | chemca
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NEET Masterclass • Module 89

Reactions of Amines & Diazonium Salts

Decode the nucleophilic nature of the nitrogen lone pair. Master the distinction tests, the aniline protection trap, and the ultimate synthetic power of the diazonium group.

By chemca Academic Team • Updated for NEET 2027

Module Focus: Nucleophilic Nitrogen & Leaving Groups

The chemistry of amines is dictated by the lone pair of electrons on nitrogen, making them strong nucleophiles. A large portion of NEET questions focuses on identifying whether an amine is $1^\circ$, $2^\circ$, or $3^\circ$ using specific chemical tests. Furthermore, when aromatic primary amines react with nitrous acid, they form Diazonium Salts containing the $-N_2^+$ group—the best leaving group in organic chemistry, enabling incredible synthetic transformations.

1. Distinction Tests for Amines

These two tests are universally used to differentiate between the classes of amines based on the number of replaceable hydrogen atoms attached to the nitrogen.

A. Carbylamine Reaction (Isocyanide Test)

Heating an amine with Chloroform ($CHCl_3$) and ethanolic KOH.

$R-NH_2 + CHCl_3 + 3KOH \xrightarrow{\Delta} \mathbf{R-NC} + 3KCl + 3H_2O$
  • Exclusively for $1^\circ$ Amines: Only primary aliphatic and aromatic amines give this test. $2^\circ$ and $3^\circ$ amines DO NOT react.
  • Observation: Forms an isocyanide ($R-NC$), characterized by an intensely foul, offensive odor.

B. Hinsberg's Test

Uses Benzenesulfonyl chloride ($C_6H_5SO_2Cl$) to distinguish between $1^\circ$, $2^\circ$, and $3^\circ$ amines based on the solubility of the resulting sulfonamide in aqueous alkali ($NaOH$).

The Hinsberg Logic
1° Amine R-NH₂ Forms Sulfonamide Ar-SO₂-N(H)-R Has Acidic H on N SOLUBLE in NaOH (Forms clear salt solution) 2° Amine R₂-NH Forms Sulfonamide Ar-SO₂-N-R₂ NO Acidic H on N INSOLUBLE in NaOH (Forms solid precipitate) 3° Amine R₃-N NO Replaceable H NO REACTION (With Hinsberg Reagent)

2. Reaction with Nitrous Acid ($HNO_2$)

Nitrous acid is highly unstable and is prepared in situ by reacting $NaNO_2$ with $HCl$. The reaction dictates whether a stable diazonium salt can be isolated.

A. Aliphatic $1^\circ$ Amines

They form aliphatic diazonium salts which are highly unstable even at low temperatures.

They instantly decompose to yield an Alcohol and massive effervescence of Nitrogen Gas ($N_2$).

$R-NH_2 \xrightarrow{NaNO_2 + HCl} R-OH + N_2\uparrow + HCl$
B. Aromatic $1^\circ$ Amines (Aniline)

They react at cold temperatures ($0 - 5^\circ\text{C}$ or $273 - 278\text{K}$) to form a stable Arenediazonium salt.

The diazonium ion is stabilized by resonance with the benzene ring.

$C_6H_5NH_2 \xrightarrow{NaNO_2 + HCl, \ 0-5^\circ\text{C}} \mathbf{C_6H_5N_2^+Cl^-}$

3. Electrophilic Aromatic Substitution (EAS) of Aniline

The $-NH_2$ group is powerfully activating and strongly ortho/para directing due to the $+M$ effect of the nitrogen lone pair. This extreme reactivity leads to major synthetic problems.

The Multi-Substitution Problem (Bromination)

If you add Bromine water ($Br_2/H_2O$) to aniline, the ring is so activated that it instantly exhaustively brominates at all ortho and para positions, yielding a white precipitate of 2,4,6-Tribromoaniline.

The Solution: Protection via Acetylation To get mono-substituted p-Bromoaniline, we must first react aniline with Acetic Anhydride to form Acetanilide. The acetyl group ($-COCH_3$) withdraws some of the nitrogen's lone pair density away from the ring via cross-conjugation, lowering its activating power. After bromination, the acetyl group is hydrolyzed off.
The Nitration Meta-Trap

Direct nitration of aniline using conc. $HNO_3$ and conc. $H_2SO_4$ yields a surprising amount of m-Nitroaniline (47%), despite $-NH_2$ being an o/p director. Why?

In the strongly acidic nitrating mixture, the basic $-NH_2$ group accepts a proton to become the Anilinium ion ($-NH_3^+$). The anilinium ion is strongly deactivating and is a meta-director.

Note: To get only p-Nitroaniline, you must use the Acetylation protection strategy described above!

4. Reactions of Diazonium Salts ($Ar-N_2^+X^-$)

The $-N_2^+$ group is an incredible leaving group (leaves as highly stable $N_2$ gas). This makes diazonium salts perfect for synthesizing a massive variety of substituted benzenes.

Reaction Name Reagents Added to $Ar-N_2^+Cl^-$ Product Formed ($Ar-Z$) Key Detail
Sandmeyer Reaction $Cu_2Cl_2/HCl$
$Cu_2Br_2/HBr$
$CuCN/KCN$
Chlorobenzene
Bromobenzene
Cyanobenzene
Uses Cuprous ($Cu^+$) salts. Better yield than Gattermann.
Gattermann Reaction $Cu \text{ powder} / HCl$
$Cu \text{ powder} / HBr$
Chlorobenzene
Bromobenzene
Uses Copper powder instead of Cuprous salts.
Balz-Schiemann Reaction 1. $HBF_4$ (Fluoroboric acid)
2. Heat ($\Delta$)
Fluorobenzene The only good way to introduce Fluorine to the ring.
Iodination Warm with $KI_{(aq)}$ Iodobenzene Does not require any Copper catalyst!
Replacement by $-OH$ Warm with $H_2O$ Phenol Temperature slightly > $5^\circ\text{C}$ required.

Azo Coupling Reactions (Dyes)

The diazonium ion acts as a weak electrophile. It attacks highly activated aromatic rings (like Phenol or Aniline) at the para position to form extended conjugated systems called Azo compounds ($-N=N-$), which are intensely colored dyes.

Coupling with Phenol

Requires mildly alkaline medium (pH 9-10).

Orange Dye

p-Hydroxyazobenzene

Coupling with Aniline

Requires mildly acidic medium (pH 4-5).

Yellow Dye

p-Aminoazobenzene

Target 180/180

NEET Grand Test: Amines Part 2

15 High-Yield Questions testing Hinsberg solubility, EAS protection traps, and Diazonium name reactions.

๐ŸŽฏ NEET 2027 Target 180

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