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NEET Crash Course Module - 84

Preparation of Aldehydes & Ketones: NEET Crash Course | chemca
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NEET Masterclass • Module 84

Preparation of Aldehydes & Ketones

Construct the polarized carbonyl core. Master selective reduction with DIBAL-H, the Dialkylcadmium trap for ketones, and essential Aromatic Name Reactions.

By chemca Academic Team • Updated for NEET 2027

Module Focus: Controlled Oxidation & Reduction

Aldehydes ($-CHO$) and Ketones ($>C=O$) are intermediate oxidation states between alcohols and carboxylic acids. Therefore, their preparation relies heavily on controlled oxidation of alcohols (stopping before the acid stage) or controlled reduction of acid derivatives (stopping before the alcohol stage). Using the wrong reagent will cause you to overshoot your target product.

1. General Methods (Alcohols & Hydrocarbons)

A. Oxidation of Alcohols
  • Primary ($1^\circ$) Alcohols: Yield Aldehydes.
    Must use PCC or $CrO_3$ in anhydrous medium to prevent over-oxidation to carboxylic acid.
  • Secondary ($2^\circ$) Alcohols: Yield Ketones. Strong oxidizers like $K_2Cr_2O_7 / H^+$ or $KMnO_4$ can safely be used because ketones strongly resist further oxidation.
B. Hydration of Alkynes (Kucherov)

Addition of water to an alkyne in the presence of $Hg^{2+} / H_2SO_4$ (Heavy metal catalyst is strictly required).

$R-C\equiv CH + H_2O \rightarrow \text{Enol} \rightleftharpoons R-CO-CH_3$

NEET Exception: Ethyne yields Acetaldehyde. ALL other alkynes yield Ketones (due to Markovnikov addition).

C. Ozonolysis of Alkenes (The Scissor Trick)

Reductive ozonolysis ($O_3$, then $Zn/H_2O$) cleaves the double bond and caps both ends with Oxygen. Zinc prevents the newly formed aldehydes from being oxidized into acids by $H_2O_2$.

2. Preparation of Aldehydes Only (Name Reactions)

These methods selectively reduce carboxylic acid derivatives down to the aldehyde stage without continuing on to primary alcohols.

1. Rosenmund Reduction

Acid chlorides (Acyl chlorides) are hydrogenated over a catalyst of Palladium deposited on Barium Sulfate ($Pd/BaSO_4$).

$R-COCl + H_2 \xrightarrow{Pd/BaSO_4} R-CHO + HCl$

The Barium Sulfate Trap:

$BaSO_4$ acts as a catalytic poison. It deactivates the Palladium enough so that the highly reactive aldehyde is NOT reduced further into a primary alcohol. (Sometimes Quinoline or Sulfur is also added to enhance poisoning).

2. Stephen Reaction

Nitriles (Cyanides) are reduced to corresponding imines using Stannous Chloride and HCl gas ($SnCl_2 / HCl$), which upon hydrolysis yield aldehydes.

$R-CN + SnCl_2 + 2HCl \rightarrow R-CH=NH \xrightarrow{H_3O^+} R-CHO + NH_3$
NEET Ultimate Reagent: DIBAL-H

Diisobutylaluminium hydride, $AlH(i-Bu)_2$, is a highly selective reducing agent used at very low temperatures ($-78^\circ\text{C}$).

  • Reduces Nitriles ($R-CN$) strictly to Aldehydes.
  • Reduces Esters ($R-COOR'$) strictly to Aldehydes.

If run at room temperature, it can over-reduce, which is why the $-78^\circ\text{C}$ condition is frequently specified in exams.

3. Preparation of Benzaldehyde

A. Etard Reaction

Controlled oxidation of Toluene. Chromyl Chloride ($CrO_2Cl_2$) in $CS_2$ forms a brown chromium complex, preventing further oxidation. Hydrolysis yields Benzaldehyde.

$C_6H_5CH_3 \xrightarrow[H_3O^+]{CrO_2Cl_2 / CS_2} C_6H_5CHO$
B. Gattermann-Koch Reaction

Direct formylation of Benzene. Uses Carbon Monoxide ($CO$) and $HCl$ gas in the presence of Anhydrous $AlCl_3/CuCl$.

$C_6H_6 + CO + HCl \xrightarrow{Anhy. \ AlCl_3} C_6H_5CHO$
Commercial Method: Side Chain Halogenation Toluene + $Cl_2 / h\nu \rightarrow$ Benzal Chloride ($C_6H_5CHCl_2$). Boiling this with water (hydrolysis at 373K) yields Benzaldehyde.

4. Preparation of Ketones Only

The most heavily tested concept here involves the use of Organometallic reagents on acid chlorides and nitriles.

The Dialkylcadmium ($R_2Cd$) Trap
R-COCl (Acid Chloride) + R'MgX R-CO-R' (Ketone) + R'MgX (again!) 3° ALCOHOL ❌ + R'₂Cd R-CO-R' (Ketone) ✅ Reaction STOPS here! R'₂Cd is too weak to react with Ketones.
From Nitriles + Grignard

Grignard reagent attacks the triple bond of a nitrile to form an imine salt, which upon acid hydrolysis yields a ketone.

$R-C\equiv N + R'MgX \rightarrow R-C(R')=NMgX$
$\xrightarrow{H_3O^+} R-CO-R'$
Friedel-Crafts Acylation

Benzene reacts with an acid chloride in the presence of anhydrous $AlCl_3$ to form an aromatic ketone.

$C_6H_6 + CH_3COCl \xrightarrow{AlCl_3} C_6H_5COCH_3$
(Acetophenone)
Target 180/180

NEET Grand Test: Carbonyl Prep

15 High-Yield Questions testing the Dialkylcadmium mechanism, specific Name Reaction reagents, and DIBAL-H rules.

๐ŸŽฏ NEET 2027 Target 180

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