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NEET Crash Course Module - 82

Reactions & Acidity of Alcohols & Phenols: NEET Crash Course | chemca
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NEET Masterclass • Module 82

Reactions & Acidity of Alcohols & Phenols

Decode the dual reactivity of the Hydroxyl group. Master the Acidity order, the Lucas Test kinetics, PCC vs $KMnO_4$ oxidations, and the iconic Reimer-Tiemann mechanism.

By chemca Academic Team • Updated for NEET 2027

Module Focus: Bond Cleavage Duality

Alcohols can act as both nucleophiles and electrophiles depending on the bond broken. When acting as a nucleophile, the O-H bond breaks (e.g., displaying acidic nature or forming esters). When acting as an electrophile (after protonation), the C-O bond breaks (e.g., reacting with HX in the Lucas test). Understanding which bond breaks explains the complete reversal of reactivity orders between primary and tertiary alcohols.

1. Acidity of Alcohols and Phenols

The acidic character relies on the stability of the conjugate base formed after releasing $H^+$.

A. Acidity of Alcohols

Alkyl groups exert a strong $+I$ (electron-donating) effect. They pump electron density onto the alkoxide ion ($R-O^-$), heavily destabilizing it.

Acidity Order: $1^\circ > 2^\circ > 3^\circ$

Trap: Water ($H_2O$) is actually MORE ACIDIC than most alcohols (except methanol)!

B. Acidity of Phenols

Phenols are a million times more acidic than alcohols. The Phenoxide ion ($C_6H_5O^-$) is massively stabilized by the delocalization of the negative charge across the aromatic ring via resonance.

Acidity: Phenols $\gg$ Water $>$ Alcohols

Substituent Effect on Phenol Acidity
  • EWG ($-NO_2, -CN, -X$): Electron-withdrawing groups stabilize the phenoxide ion by dispersing the negative charge. They INCREASE acidity. The effect is maximum at ortho and para positions.
  • EDG ($-CH_3, -OCH_3$): Electron-donating groups destabilize the phenoxide ion by intensifying the negative charge. They DECREASE acidity.
Picric Acid (2,4,6-Trinitrophenol) > p-Nitrophenol > Phenol > o-Cresol (o-Methylphenol)

2. Reactions of Alcohols (C-O Bond Cleavage)

Reactions involving the cleavage of the C-O bond proceed via a carbocation intermediate. Therefore, the reactivity order is exactly reversed: $3^\circ > 2^\circ > 1^\circ$.

The Lucas Test (Distinguishing $1^\circ, 2^\circ, 3^\circ$)

Reacting alcohols with Lucas Reagent (Conc. $HCl$ + Anhydrous $ZnCl_2$) forms insoluble alkyl chlorides, which appear as a white turbidity (cloudiness).

Tertiary ($3^\circ$)

Forms highly stable $3^\circ$ carbocation.

Turbidity appears IMMEDIATELY.

Secondary ($2^\circ$)

Forms moderately stable $2^\circ$ carbocation.

Turbidity appears after ~5 minutes.

Primary ($1^\circ$)

Highly unstable $1^\circ$ carbocation.

NO turbidity at room temp. Requires heating.

Reaction with Phosphorus Halides and $SOCl_2$

Alcohols react with $PCl_5$, $PCl_3$, and $SOCl_2$ (Thionyl chloride) to form alkyl chlorides. As seen in Haloalkanes, reacting with $SOCl_2$ is the best method because the by-products ($SO_2$ and $HCl$) are escapable gases.

3. Oxidation & Dehydrogenation of Alcohols

Oxidation essentially involves the removal of hydrogen from the carbon bearing the $-OH$ group (the $\alpha$-carbon) and the oxygen itself, forming a $C=O$ double bond.

Alcohol Type Mild Oxidation (PCC or $CrO_3$) Strong Oxidation ($KMnO_4$, $K_2Cr_2O_7$) Hot Copper Tube ($Cu/573\text{K}$)
Primary ($1^\circ$) Aldehyde Carboxylic Acid Aldehyde (Dehydrogenation)
Secondary ($2^\circ$) Ketone Ketone Ketone (Dehydrogenation)
Tertiary ($3^\circ$) No Reaction No Reaction (Under normal conditions) ALKENE (Dehydration)
NEET Trap: Tertiary Alcohols Tertiary alcohols lack an $\alpha$-hydrogen, making standard oxidation impossible. When passed over heated Copper ($Cu$ at $573\text{K}$), instead of dehydrogenation, they undergo $\beta$-elimination (Dehydration) to form an Alkene.

4. Specific Reactions of Phenols

The $-OH$ group in phenol is highly activating and ortho/para directing. Electrophilic Aromatic Substitution (EAS) occurs much faster than in benzene.

A. The Solvent Effect in Bromination

Bromine Water ($Br_2/H_2O$)

In a highly polar solvent like water, phenol ionizes significantly to form the phenoxide ion, which activates the ring immensely.

Yields: 2,4,6-Tribromophenol
(White Precipitate)
Bromine in $CS_2$ or $CHCl_3$ at 273 K

In a non-polar solvent at low temperatures, ionization is suppressed. The ring is less activated.

Yields: Mono-bromination
(p-Bromophenol is major)

B. Name Reactions (Extremely High Yield)

1. Reimer-Tiemann Reaction

Treating phenol with Chloroform ($CHCl_3$) and aqueous NaOH, followed by acidification.

Product: Salicylaldehyde
(o-Hydroxybenzaldehyde)
Trap: The intermediate electrophile generated is Dichlorocarbene ($:CCl_2$).
2. Kolbe's Reaction

Treating Sodium phenoxide with Carbon Dioxide ($CO_2$) under high pressure and temperature, followed by acidification.

Product: Salicylic Acid
(2-Hydroxybenzoic acid)
Trap: Salicylic acid is the starting material to synthesize Aspirin (acetylsalicylic acid).

C. Oxidation with Chromic Acid ($Na_2Cr_2O_7 / H_2SO_4$)

Phenol undergoes vigorous oxidation with strong oxidizing agents to form a conjugated diketone.

Phenol $\xrightarrow{Na_2Cr_2O_7, \ H_2SO_4}$ p-Benzoquinone (Conjugated Diketone)
Target 180/180

NEET Grand Test: Alcohol & Phenol Rxns

15 High-Yield Questions testing acidity orders, Reimer-Tiemann intermediates, and oxidation anomalies.

๐ŸŽฏ NEET 2027 Target 180

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