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NEET Crash Course Module - 73

Magnetic Behavior, Colour & Alloys of d-Block: NEET Crash Course | chemca
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NEET Crash Course • Module 73

Magnetic Behavior, Colour & Alloys

Decode the defining characteristics of transition metals. Master the spin-only magnetic moment formula, d-d transition colors, and the lattice physics of interstitial compounds.

By chemca Academic Team • Updated for NEET 2027

Module Focus: The Unpaired Electron Advantage

The defining feature of transition metals is their incompletely filled d-orbitals. These unpaired d-electrons are directly responsible for the magnetic properties (paramagnetism) and the vibrant colors exhibited by their complexes. Furthermore, the similar atomic sizes of these metals allow them to form diverse alloys and trap small non-metals to form highly durable interstitial compounds.

1. Magnetic Properties

Substances can be classified as Diamagnetic (repelled by a magnetic field, zero unpaired electrons) or Paramagnetic (attracted by a magnetic field, presence of unpaired electrons). Transition metal ions are predominantly paramagnetic.

The Spin-Only Magnetic Moment Formula

For compounds of the 3d series, the orbital angular momentum is heavily quenched (suppressed) by the surrounding environment. The magnetic moment relies almost entirely on the electron spin.

$\mu = \sqrt{n(n+2)} \text{ BM}$
Where $\mu$ = Magnetic Moment
$n$ = Number of Unpaired Electrons
BM = Bohr Magneton (unit)
NEET Numerical Hack: The Decimal Trick

You do not need to calculate square roots in the exam. The integer part of the magnetic moment is ALWAYS equal to the number of unpaired electrons ($n$).

Ion Example Configuration Unpaired e⁻ ($n$) $\mu$ Value (BM)
$Ti^{3+}$ $3d^1$ 1 $\sqrt{3} \approx \mathbf{1}.73$
$Ni^{2+}$ $3d^8$ 2 $\sqrt{8} \approx \mathbf{2}.83$
$Fe^{2+}$ $3d^6$ 4 $\sqrt{24} \approx \mathbf{4}.90$
$Mn^{2+}, Fe^{3+}$ $3d^5$ 5 (Maximum) $\sqrt{35} \approx \mathbf{5}.92$

2. Formation of Coloured Ions

Most transition metal compounds are highly colored in solid state and in solution. This color arises from the absorption of visible light, which excites an electron from a lower energy d-orbital to a higher energy d-orbital.

d-d Transitions

In the presence of ligands (like water molecules), the five degenerate d-orbitals split into two sets of different energies ($t_{2g}$ and $e_g$).

An unpaired electron jumps between these split levels, absorbing a specific color of light. The transmitted (complementary) color is what we see.

The Colourless Exceptions

For a d-d transition to occur, there MUST be at least one unpaired d-electron, AND there must be space in a higher d-orbital.

  • $d^0$ Systems: No electrons to excite. $\rightarrow$ Colourless. (e.g., $Sc^{3+}, Ti^{4+}, Zn^{2+}$)
  • $d^{10}$ Systems: Orbitals are full, no space to jump. $\rightarrow$ Colourless. (e.g., $Zn^{2+}, Cu^+, Ag^+$)
NEET Mega Trap: $KMnO_4$ and $K_2Cr_2O_7$

In the Permanganate ion ($MnO_4^-$), Manganese is in the $+7$ state, meaning it is strictly $3d^0$. It has NO d-electrons. Yet, $KMnO_4$ is intensely purple!

Why? The color is due to Ligand-to-Metal Charge Transfer (LMCT), where an electron from Oxygen momentarily jumps to the empty d-orbitals of Manganese, NOT d-d transitions. Same logic applies to orange Dichromate ($Cr_2O_7^{2-}$).

3. Formation of Alloys

An alloy is a solid solution of two or more elements in a metallic matrix. Transition metals form extensive alloys with each other because they satisfy the Hume-Rothery Rules.

The 15% Rule

Transition metals have very similar atomic radii. Because the difference in their atomic radii is less than 15%, atoms of one metal can easily substitute for atoms of another metal in the crystal lattice without heavily distorting it.

Examples: Brass ($Cu + Zn$), Bronze ($Cu + Sn$)

4. Interstitial Compounds

Transition metal crystal lattices have microscopic empty spaces (voids/interstices). When extremely small non-metal atoms (like Hydrogen, Carbon, or Nitrogen) get trapped inside these voids, Interstitial Compounds are formed.

Properties of Interstitial Compounds

These compounds are typically non-stoichiometric (e.g., $TiH_{1.73}, VH_{0.56}$) and are neither purely ionic nor purely covalent. The trapping of the small atom drastically alters physical properties while preserving metallic nature.

1. Higher Melting Points

They have melting points significantly higher than those of the pure metals. The trapped atoms increase the lattice strain and strengthen the metal-metal bonds.

2. Extreme Hardness

They become extremely hard. Some borides and carbides (like Tungsten Carbide, $WC$) approach the hardness of diamond.

3. Retained Conductivity

They completely retain their metallic conductivity because the delocalized electrons in the metal lattice are not consumed in bonding.

4. Chemical Inertness

They become highly chemically inert, resisting reactions with typical acids or bases compared to the pure metal.

Target 180/180

NEET Grand Test: d-Block Properties

15 High-Yield Questions testing spin-only moments, LMCT traps, and interstitial lattice properties.

๐ŸŽฏ NEET 2027 Target 180

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