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NEET Crash Course Module - 53

Preparation of Benzene: NEET Crash Course | chemca
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NEET Masterclass • Module 53

Preparation of Benzene

Synthesize the fundamental aromatic ring. Master the Decarboxylation of Benzoate, Phenol reduction with Zinc, and the highly-tested Diazonium salt pathways.

By chemca Academic Team • Updated for NEET 2027

Module Focus: Entering the Aromatic World

Benzene ($C_6H_6$) is the simplest and most vital aromatic hydrocarbon. While it can be isolated commercially from coal tar or petroleum, laboratory synthesis requires specific reagents to strip functional groups off substituted benzene rings. In NEET, you are frequently tested on the reagents required to remove $-OH$, $-COOH$, or $-N_2^+Cl^-$ groups to yield pristine benzene, along with their associated by-products.

1. Cyclic Polymerization of Ethyne (Review)

When Ethyne ($HC\equiv CH$) is passed through a Red Hot Iron (or Copper) tube at 873 K, three molecules trimerize to form the aromatic benzene ring. This is a crucial reaction for converting aliphatic compounds into aromatic compounds.

$3 \ HC\equiv CH \xrightarrow{\text{Red Hot Fe Tube, } 873\text{K}} C_6H_6 \ (\text{Benzene})$

2. Decarboxylation of Aromatic Acids

Sodium salt of benzoic acid (Sodium Benzoate) is strongly heated with Soda-Lime to yield benzene.

What is Soda-Lime?

It is a mixture of Sodium Hydroxide ($NaOH$) and Calcium Oxide ($CaO$) in a 3:1 ratio.

Role of CaO (Quicklime):

  • $NaOH$ is highly hygroscopic (absorbs water). $CaO$ keeps it dry.
  • It prevents the mixture from fusing at lower temperatures, making it easier to handle.
The Reaction
$C_6H_5COONa + NaOH \xrightarrow{CaO, \ \Delta} C_6H_6 + Na_2CO_3$

The carboxylate group ($-COONa$) is completely removed as Sodium Carbonate ($Na_2CO_3$).

3. Reduction of Phenol

Phenol ($C_6H_5OH$) can be reduced directly to Benzene by passing its vapors over heated Zinc dust. This is a classic oxidation-reduction reaction where Zinc strips the oxygen from the aromatic ring.

Reduction Pathway: Phenol to Benzene
OH Phenol + Zn ฮ” (Heat) O-Transfer Benzene + ZnO
NEET Hidden Route: From Grignard Reagent

Benzene can also be prepared by the hydrolysis of Phenylmagnesium bromide ($C_6H_5MgBr$) in an acidic medium.

$C_6H_5MgBr + H_2O \xrightarrow{H^+} C_6H_6 + Mg(OH)Br$

4. Reduction of Diazonium Salts

Benzene diazonium chloride ($C_6H_5N_2^+Cl^-$) is a highly reactive, incredibly useful intermediate (prepared from Aniline via diazotization). It can be reduced to pure benzene using mild reducing agents. This is one of the most frequently tested conversions in NEET.

A. Hypophosphorous Acid ($H_3PO_2$)

Reacting the diazonium salt with $H_3PO_2$ (also called phosphinic acid) in the presence of water.

$ArN_2^+Cl^- + H_3PO_2 + H_2O \rightarrow ArH + N_2 + H_3PO_3 + HCl$

Oxidation By-product: Phosphorous Acid ($H_3PO_3$)

B. Ethanol ($CH_3CH_2OH$)

Reacting the diazonium salt directly with Ethanol. Ethanol acts as the reducing agent.

$ArN_2^+Cl^- + CH_3CH_2OH \rightarrow ArH + N_2 + CH_3CHO + HCl$

Oxidation By-product: Ethanal / Acetaldehyde ($CH_3CHO$)

The Diazonium Reduction Mechanism (with $H_3PO_2$)
N₂+Cl- Benzene Diazonium Chloride + H₃PO₂ + H₂O [H] Reduction H Benzene + H₃PO₃ N₂ ↑ HCl
Target 180/180

NEET Grand Test: Benzene Prep

15 High-Yield Questions testing reagents, redox by-products, and conversion pathways.

๐ŸŽฏ NEET 2027 Target 180

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