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NEET Crash Course Module - 43

Quantitative Analysis of Organic Compounds: NEET Crash Course | chemca
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NEET Masterclass • Module 43

Quantitative Analysis of Organic Compounds

Move from "what" is present to "how much" is present. Master the critical formulas of Liebig's, Dumas, Kjeldahl's, and Carius methods to secure your Physical-Organic numerical marks.

By chemca Academic Team • Updated for NEET 2027

Module Focus: The Path to the Empirical Formula

Once qualitative analysis confirms the presence of specific elements, quantitative analysis determines their exact mass percentages. These percentages are the foundation for calculating the Empirical Formula. In NEET, you must memorize the reagents used to trap the elements and the mathematical formulas used to back-calculate their mass. Let $m$ always represent the total mass of the organic compound taken.

1. Estimation of Carbon & Hydrogen (Liebig's Method)

The organic compound is oxidized by heating with dry $CuO$. Carbon converts to $CO_2$ and Hydrogen to $H_2O$.

The $H_2O$ is trapped using anhydrous $CaCl_2$ or $Mg(ClO_4)_2$ (mass increases).
The $CO_2$ is trapped using concentrated $KOH$ solution (mass increases).

Percentage of Carbon

Since $44\text{g}$ of $CO_2$ contains $12\text{g}$ of Carbon:

$\% C = \frac{12}{44} \times \frac{m_{CO_2}}{m} \times 100$
Percentage of Hydrogen

Since $18\text{g}$ of $H_2O$ contains $2\text{g}$ of Hydrogen:

$\% H = \frac{2}{18} \times \frac{m_{H_2O}}{m} \times 100$

2. Estimation of Nitrogen

A. Dumas Method

The organic compound is heated with $CuO$ in an atmosphere of $CO_2$. Nitrogen is liberated as free $N_2$ gas. Any nitrogen oxides formed are reduced back to $N_2$ by passing over heated copper gauze. The $N_2$ gas is collected over an aqueous $KOH$ solution (which absorbs the $CO_2$ carrier gas).

$\% N = \frac{28}{22400} \times \frac{V_{\text{STP}}}{m} \times 100$

Note: $V_{\text{STP}}$ is the volume of $N_2$ gas converted to STP (Standard Temp & Pressure) in mL.

Aqueous Tension Trap: Remember to subtract the aqueous tension from the atmospheric pressure to get the pressure of dry $N_2$ before using $P_1V_1/T_1 = P_2V_2/T_2$.
$P_{dry} = P_{total} - \text{Aqueous Tension}$

B. Kjeldahl's Method

A highly important method, especially for fertilizers and foods. Instead of $N_2$ gas, Nitrogen is converted into Ammonia ($NH_3$).

Visualizing Kjeldahl's Process
1. Digestion Heat with conc. $H_2SO_4$ Catalyst: $CuSO_4$ Forms $(NH_4)_2SO_4$ 2. Distillation Boil with excess $NaOH$ Releases $NH_3$ (gas) 3. Titration Absorb in known volume of standard $H_2SO_4$
$\% N = \frac{1.4 \times M \times \text{Basicity} \times V}{m} = \frac{1.4 \times N \times V}{m}$

Where:
M = Molarity of standard acid used to absorb $NH_3$
N = Normality of the acid ($N = M \times \text{Basicity}$)
V = Volume (in mL) of the acid neutralized by $NH_3$.
(Calculate V by taking total volume of acid taken minus the volume of acid left unreacted, determined by back-titration with NaOH).

NEET Mega Trap: When does Kjeldahl's Method FAIL?

Kjeldahl's method relies on converting organic nitrogen into $(NH_4)_2SO_4$. However, certain compounds are too stable or structured differently, and their nitrogen will NOT convert to ammonium sulfate under these conditions.

  • Nitro compounds ($-NO_2$)
  • Azo compounds ($-N=N-$)
  • Nitrogen present in aromatic rings (e.g., Pyridine, Quinoline)

For these compounds, the Dumas method must be used.

3. Estimation of Halogens and Sulfur (Carius Method)

The organic compound is heated with fuming Nitric Acid ($HNO_3$) in a sealed, hard glass tube known as a Carius tube. Carbon and Hydrogen are oxidized to $CO_2$ and $H_2O$.

A. Halogens ($X$)

Silver Nitrate ($AgNO_3$) is added. The halogen forms a precipitate of Silver Halide ($AgX$), which is washed, dried, and weighed.

$\% X = \frac{\text{Atomic Mass of X}}{\text{Molar Mass of } AgX} \times \frac{m_{AgX}}{m} \times 100$
  • $AgCl$ Molar Mass = 143.5 g/mol
  • $AgBr$ Molar Mass = 188 g/mol
  • $AgI$ Molar Mass = 235 g/mol
B. Sulfur ($S$)

Sulfur is oxidized to Sulfuric acid ($H_2SO_4$). Barium Chloride ($BaCl_2$) is added to precipitate Barium Sulfate ($BaSO_4$).

$\% S = \frac{32}{233} \times \frac{m_{BaSO_4}}{m} \times 100$

Where 32 is atomic mass of S, and 233 is molar mass of $BaSO_4$.

4. Estimation of Phosphorus and Oxygen

Estimation of Phosphorus

Heated with fuming $HNO_3$ to oxidize P to Phosphoric acid ($H_3PO_4$). It is precipitated as magnesium ammonium phosphate, which is then ignited to yield Magnesium Pyrophosphate ($Mg_2P_2O_7$).

$\% P = \frac{62}{222} \times \frac{m_{Mg_2P_2O_7}}{m} \times 100$

Note: 62 is the mass of 2 Phosphorus atoms, 222 is the molar mass of $Mg_2P_2O_7$.

Estimation of Oxygen (Aluise's Method)

Usually, Oxygen is estimated by difference: $\%O = 100 - (\%C + \%H + \%N...)$

However, in a direct method, the compound is decomposed to release $O_2$, which is passed over hot carbon to form $CO$. The $CO$ is then oxidized by Iodine Pentoxide ($I_2O_5$) into $CO_2$ while liberating $I_2$.

$5CO + I_2O_5 \rightarrow I_2 + 5CO_2$
Target 180/180

NEET Grand Test: Quantitative Analysis

15 High-Yield Questions targeting numerical formulas, standard precipitates, and Kjeldahl limitations.

๐ŸŽฏ NEET 2027 Target 180

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