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Vapour Pressure & Boiling Point

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States of Matter (Liquid State)

Vapour Pressure

Dynamic Equilibrium, Boiling Points, and the Clausius-Clapeyron Equation.

By chemca Team • Updated Aug 2026

When a liquid is kept in a closed container, molecules with high kinetic energy escape from the surface into the vapor phase (Evaporation). Simultaneously, some vapor molecules strike the liquid surface and are recaptured (Condensation). Eventually, a Dynamic Equilibrium is established.

1. What is Vapour Pressure?

Vapour Pressure is defined as the pressure exerted by the vapor of a liquid when it is in dynamic equilibrium with its liquid phase in a closed container at a given temperature.

$$ \text{Rate of Evaporation} = \text{Rate of Condensation} $$
Note: In an open container, the vapor molecules drift away, so equilibrium is never reached. The liquid simply evaporates completely over time. Vapour pressure can only be measured in a closed system.

2. Factors Affecting Vapour Pressure

Vapour pressure is a characteristic property of a liquid at a specific temperature. It depends on exactly two things:

1. Nature of the Liquid (Intermolecular Forces)

  • Liquids with weak intermolecular forces (like ether or acetone) allow molecules to escape easily. They have a high vapour pressure and are called volatile liquids.
  • Liquids with strong intermolecular forces (like water, which has hydrogen bonding) hold tightly to their molecules. They have a low vapour pressure.

2. Temperature

  • As temperature increases, the average kinetic energy of the liquid molecules increases.
  • More molecules gain enough energy to overcome the intermolecular forces and escape into the vapor phase.
  • Therefore, Vapour Pressure increases non-linearly (exponentially) with Temperature.
The Ultimate Exam Trap: Vapour pressure does NOT depend on the surface area of the liquid or the volume of the container. A drop of water and a bucket of water in identical closed $1 \text{ L}$ flasks at $25^\circ C$ will exert the exact same vapour pressure once equilibrium is reached!

3. Vapour Pressure Graph & Boiling Point

The Boiling Point of a liquid is defined as the temperature at which its vapour pressure becomes exactly equal to the external atmospheric pressure.

1 atm (760 mmHg) External Pressure Vapour Pressure Temperature (°C) 0 Diethyl Ether 34.6 Water 100

Interpretation: Diethyl ether has weaker intermolecular forces, so its vapour pressure reaches $1 \text{ atm}$ at a much lower temperature ($34.6^\circ C$) compared to water ($100^\circ C$).

  • Normal Boiling Point: Boiling point when external pressure is $1 \text{ atm}$ ($760 \text{ mmHg}$). For water, it is $100^\circ C$.
  • Standard Boiling Point: Boiling point when external pressure is $1 \text{ bar}$ ($0.987 \text{ atm}$). For water, it is $99.6^\circ C$.
  • Pressure Cooker Effect: By sealing a pot, the pressure inside builds up above $1 \text{ atm}$. The water must reach a higher temperature before its vapour pressure equals this new, higher internal pressure, cooking food faster.

4. Clausius-Clapeyron Equation

The quantitative relationship between Vapour Pressure ($P$) and Absolute Temperature ($T$) is given by the Clausius-Clapeyron Equation. This is crucial for solving numericals in JEE Advanced and NEET.

$$\ln \left( \frac{P_2}{P_1} \right) = \frac{\Delta H_{vap}}{R} \left( \frac{1}{T_1} - \frac{1}{T_2} \right)$$

Or using Base-10 Logarithms ($2.303 \log x = \ln x$):

$$\log \left( \frac{P_2}{P_1} \right) = \frac{\Delta H_{vap}}{2.303 R} \left( \frac{T_2 - T_1}{T_1 T_2} \right)$$
  • $P_1, P_2$: Vapour pressures at temperatures $T_1$ and $T_2$ (in Kelvin).
  • $\Delta H_{vap}$: Enthalpy (Heat) of Vaporization of the liquid.
  • $R$: Universal Gas Constant ($8.314 \text{ J K}^{-1}\text{mol}^{-1}$).

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