Search This Blog

Fehlings test masterclass

Fehling's Test: Detection of Aliphatic Aldehydes & Reducing Sugars | Chemca
Exhaustive Guide | Organic Chemistry

Fehling's Test: Detection of Aliphatic Aldehydes & Reducing Sugars

By Chemca Editorial Team Last Updated: August 2026 22 min read

1. Introduction: What is Fehling's Test?

Fehling's Test is a classic qualitative organic chemistry test used primarily to differentiate between water-soluble carbohydrate and ketone functional groups, and as a test for reducing sugars and non-reducing sugars. Specifically, it is used to detect the presence of aliphatic aldehydes.

Like Tollens' test, it utilizes a mild oxidizing agent. However, Fehling's reagent is a weaker oxidizing agent than Tollens' reagent. Because of this subtle difference in redox potential, Fehling's test is uniquely able to distinguish aliphatic aldehydes from aromatic aldehydes.

2. The Reagents: Fehling's A and Fehling's B

Fehling's solution is notoriously unstable if kept as a single mixture. Therefore, it is always stored as two separate solutions in the laboratory, which are mixed in equal volumes immediately before conducting the test.

  • Fehling's Solution A: An aqueous solution of Copper(II) sulfate ($CuSO_4 \cdot 5H_2O$). It is deep blue in color.
  • Fehling's Solution B: A clear, colorless aqueous solution containing a strong alkali (usually Sodium Hydroxide, $NaOH$) and a chelating agent, Sodium Potassium Tartrate (also known as Rochelle salt).

Why is Rochelle Salt necessary?

When you mix $CuSO_4$ with $NaOH$, normally a pale blue precipitate of Copper(II) hydroxide ($Cu(OH)_2$) would form, pulling the copper ions out of solution. The tartrate ions from Rochelle salt act as bidentate ligands, chelating the $Cu^{2+}$ ions and keeping them in a stable, soluble, deep-blue complex known as the bistartratocuprate(II) complex.

3. Reaction Mechanism & Observations

When a test compound containing an aliphatic aldehyde ($R-CHO$) is added to the freshly mixed Fehling's reagent and heated in a water bath, a redox reaction occurs.

  • Oxidation: The aldehyde is oxidized to a carboxylate anion ($R-COO^-$) because the medium is highly alkaline.
  • Reduction: The deep blue $Cu^{2+}$ complex is reduced to Copper(I) oxide ($Cu_2O$), which is highly insoluble in water.
$$R-CHO + 2Cu^{2+} + 5OH^- \xrightarrow{\Delta} R-COO^- + \underset{\text{Brick-Red Ppt}}{Cu_2O\downarrow} + 3H_2O$$

Observation: A positive test is indicated by the deep blue solution transforming into a brick-red precipitate of Copper(I) oxide. (Note: Depending on concentration, the color may shift from blue $\rightarrow$ green $\rightarrow$ yellow $\rightarrow$ orange $\rightarrow$ brick red).

4. The Aromatic Exception: Why Benzaldehyde Fails

This is the most heavily tested distinction in competitive exams regarding Fehling's test.

Aromatic aldehydes (like benzaldehyde) do NOT give a positive Fehling's test.

In benzaldehyde, the carbonyl group is conjugated with the aromatic $\pi$-system. This resonance stabilization makes the aldehyde carbon less electrophilic and harder to oxidize. Because the $Cu^{2+}$ complex in Fehling's solution is a weaker oxidizing agent than the $Ag^+$ complex in Tollens' reagent, it simply lacks the thermodynamic driving force to oxidize benzaldehyde. (Tollens' will successfully oxidize benzaldehyde).

5. Application in Biochemistry: Reducing Sugars

Fehling's test is heavily utilized in carbohydrate chemistry to test for reducing sugars. A reducing sugar is any sugar that is capable of acting as a reducing agent because it has a free aldehyde group or a free ketone group that can isomerize.

  • Aldoses (e.g., Glucose): Contain a free aldehyde group in their open-chain form. They rapidly form the brick-red precipitate.
  • Ketoses (e.g., Fructose): While standard ketones fail Fehling's test, fructose is an $\alpha$-hydroxy ketone. In the strongly alkaline environment of Fehling's reagent, fructose undergoes the Lobry de Bruyn-van Ekenstein transformation, isomerizing into glucose and mannose (aldoses), which then react positively.
  • Non-Reducing Sugars (e.g., Sucrose): Sucrose is a disaccharide where the anomeric carbons of both glucose and fructose are tied up in a glycosidic bond. It cannot ring-open to form an aldehyde, so it gives a negative Fehling's test.

6. Fehling's vs. Benedict's Test

Benedict's test is a variation of Fehling's test and operates on the exact same chemical principle (reduction of $Cu^{2+}$ to $Cu_2O$). However, the reagents differ slightly to make Benedict's solution more stable.

Feature Fehling's Test Benedict's Test
Complexing Agent Tartrate (Rochelle Salt) Citrate
Alkali Used Strong ($NaOH$ or $KOH$) Mild ($Na_2CO_3$, Sodium Carbonate)
Stability Unstable (must be mixed fresh) Stable (stored as single solution)
Primary Use Organic synthesis / Lab distinctions Biological assays (e.g., glucose in urine)
๐Ÿงช Functional Group Tests Hub

๐Ÿ”ฌ Master Distinction Reactions

Learn all important functional group identification tests, reagents, and reaction principles including Tollens', Baeyer's, Iodoform, Hinsberg's, and more. A high-yield revision resource for JEE Main, JEE Advanced, and NEET.

๐Ÿš€ Explore the Complete Hub
Mega Challenge

Ultimate 25-Question Quiz

Test your understanding of Fehling's A & B, redox mechanisms, reducing sugars, and benzaldehyde exceptions.

Chemca.in

Providing exhaustive, high-yield chemistry resources to help students master concepts for JEE, NEET, and university curricula.

© 2026 Chemca. All rights reserved.

Powered by

๐Ÿ“š Also Read

Lecture Notes

No comments:

Post a Comment

Featured Post

Most Important Name Reactions in Organic Chemistry | Chemca