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Exam Master Review Sheet - Reaction Mechanism

Chemca Formula Sheet - Reaction Mechanism

CHEMCA

EXAM MASTER FORMULA SHEET

Organic Reaction Mechanisms

Core Pathways for JEE Main, Advanced & NEET

1. Reagents & Bond Fission

Electrophiles ($E^+$)

Electron-deficient species (Lewis Acids). Attack at electron-rich sites.

Charged: $H^+, Cl^+, NO_2^+, CH_3^+$

Neutral (Incomplete octet): $AlCl_3, BF_3, SO_3, :CH_2$ (Carbene)

Nucleophiles ($Nu^-$)

Electron-rich species (Lewis Bases). Attack at electron-deficient sites.

Charged: $OH^-, CN^-, X^-, RO^-$

Neutral (Lone pairs): $NH_3, H_2O, R-OH$

Ambidentate Nucleophiles: Have two donor atoms but attack through one at a time. E.g., $-CN$ (can attack via C or N) and $-NO_2$ (via N or O).

Bond Fission Types

Homolytic Fission:
$A-B \to A^\bullet + B^\bullet$

Symmetrical cleavage forming Free Radicals.

Favored by: Light ($h\nu$), Heat ($\Delta$), Peroxides, Radicals (HELP).

Heterolytic Fission:
$A-B \to A^+ + B^-$

Unsymmetrical cleavage forming Ions (Carbocation/Carbanion).

Favored by: Polar Solvents, High EN difference, Acids/Bases.

2. Aliphatic Nucleophilic Substitution

Feature $S_N1$ (Unimolecular) $S_N2$ (Bimolecular)
Kinetics & Rate Rate $= k[R-X]$ Rate $= k[R-X][Nu^-]$
Mechanism 2-step (Carbocation intermediate formed). Rearrangements possible! 1-step concerted (Pentacoordinate Transition State). No rearrangements.
Stereochemistry Racemization
(slight net inversion due to ion-pair)
100% Walden Inversion
(Backside attack)
Substrate Reactivity Benz./Allyl > $3^\circ > 2^\circ > 1^\circ > CH_3$ $CH_3 > 1^\circ > 2^\circ > 3^\circ$
(Steric hindrance dominates)
Favored Solvent Polar Protic ($H_2O, EtOH, HCOOH$)
Stabilizes both carbocation and leaving group.
Polar Aprotic (Acetone, DMF, DMSO)
Leaves nucleophile naked and reactive.
Nucleophilicity Trends (Halides):
  • In Polar Protic Solvents: $I^- > Br^- > Cl^- > F^-$
    (Smaller ions get heavily solvated/blocked).
  • In Polar Aprotic Solvents: $F^- > Cl^- > Br^- > I^-$
    (True basicity order dominates).
Internal Substitution ($S_Ni$):

Reaction of alcohols with $SOCl_2$ (Darzen's process).

  • • Without Pyridine: Retention of configuration ($S_Ni$).
  • • With Pyridine: Inversion of configuration ($S_N2$).

3. Elimination Mechanisms ($E1, E2, E1cb$)

$E1$ (Unimolecular)
  • Rate: $k[Substrate]$
  • Intermediate: Carbocation (Rearrangements possible!).
  • Product: Saytzeff alkene (most stable).
  • Reagents: Weak base, high heat (e.g., Conc. $H_2SO_4/\Delta$).
$E2$ (Bimolecular)
  • Rate: $k[Substrate][Base]$
  • Intermediate: None (Concerted Transition State).
  • Stereochem: Anti-periplanar (H and LG must be anti).
  • Reagents: Strong base (e.g., Alc. $KOH$).
$E1cb$ (Conjugate Base)
  • Intermediate: Carbanion.
  • Condition: Requires a very poor leaving group (like $-F, -NR_3^+$) and a strong Electron Withdrawing Group to stabilize the carbanion.
  • Product: Hofmann alkene (less substituted).
Saytzeff vs Hofmann Rule

Saytzeff (Zaitsev) Rule: Major product is the more substituted alkene (thermodynamically more stable).
Favored by: Standard leaving groups (Cl, Br, I) and small bases ($EtO^-$).


Hofmann Rule: Major product is the less substituted alkene (kinetic control).
Favored by: Bulky bases ($t-BuO^-$), Poor leaving groups ($F^-$), or Steric hindrance in substrate.

Elimination vs Substitution:
High Temperature ($\Delta$) + Strong/Bulky Base
$\implies$ Elimination ($E2/E1$)
Low Temperature + Strong Nucleophile
$\implies$ Substitution ($S_N2$)

4. Electrophilic Addition ($Ad_E$) to Alkenes

Characteristic reaction of alkenes and alkynes. The $\pi$-bond breaks, forming a carbocation intermediate (which can rearrange!).

Markovnikov's Rule

When an unsymmetrical reagent ($HX, H_2O/H^+$) adds to an unsymmetrical alkene, the negative part goes to the carbon with fewer hydrogen atoms.

Underlying Reality: The reaction proceeds via the most stable Carbocation. Rearrangements (Hydride or Alkyl shifts) WILL occur if a more stable carbocation can be formed!

Kharasch (Peroxide / Anti-Mk) Effect

The negative part goes to the carbon with more hydrogen atoms.

  • Valid ONLY for $HBr$ in the presence of Peroxides ($R_2O_2$).
  • Fails for $HCl$ and $HI$ due to endothermic propagation steps.
  • Mechanism: Free Radical Addition (No carbocations, NO rearrangements).
Test for Unsaturation ($Br_2 / CCl_4$): Addition of Bromine causes the reddish-brown color to discharge.
Mechanism involves a cyclic bromonium ion intermediate leading to Anti-Addition (Trans product).

5. Electrophilic Aromatic Substitution ($S_EAr$)

Aromatic rings undergo substitution rather than addition to preserve resonance stabilization (aromaticity).

Reaction Name Standard Reagents Active Electrophile
Nitration Conc. $HNO_3$ + Conc. $H_2SO_4$ ($\Delta$) $NO_2^+$ (Nitronium)
Halogenation $Cl_2$ or $Br_2$ + Anhyd. $FeCl_3$ / $AlCl_3$ $Cl^+$ or $Br^+$
Sulphonation Fuming $H_2SO_4$ (Oleum) $SO_3$ (Neutral)
F.C. Alkylation $R-X$ + Anhyd. $AlCl_3$ $R^+$ (Can rearrange!)
F.C. Acylation $R-COCl$ + Anhyd. $AlCl_3$ $R-C^+=O$ (No rearrangement)
Activating Groups ($o/p$ Directing)

Increase electron density on the ring (via $+M$ or $+H$). Direct incoming $E^+$ to ortho and para positions.

$-O^-, -NH_2, -OH, -OR, -NHCOR, -R$

Para is usually the major product due to less steric hindrance at the ortho position.

Deactivating Groups ($m$ Directing)

Decrease electron density on the ring (via $-M$). Direct incoming $E^+$ to the meta position.

$-NO_2, -CN, -SO_3H, -CHO, -COOH$

Halogen Anomaly:

Halogens ($-Cl, -Br$) are Deactivating ($-I > +M$) but are Ortho/Para directing.

6. Free Radical Substitution (FRS)

Alkane Halogenation

Occurs in presence of UV light ($h\nu$) or heat.

  1. 1. Initiation: $Cl_2 \xrightarrow{h\nu} 2Cl^\bullet$
  2. 2. Propagation:
    $CH_4 + Cl^\bullet \to CH_3^\bullet + HCl$
    $CH_3^\bullet + Cl_2 \to CH_3Cl + Cl^\bullet$
  3. 3. Termination: $Cl^\bullet + Cl^\bullet \to Cl_2$
    $CH_3^\bullet + CH_3^\bullet \to C_2H_6$

Allylic / Benzylic Bromination

Reagent: NBS (N-Bromosuccinimide) with $h\nu$ or Peroxide.

Specifically targets the allylic ($C=C-CH_3$) or benzylic ($Ph-CH_3$) position due to the high stability of resonance-stabilized allylic/benzylic free radicals.

$R-CH_2-CH=CH_2 \xrightarrow{NBS} R-CH(Br)-CH=CH_2$

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