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Tishchenko Reaction: Mechanism & Ester Synthesis | Chemca

Tishchenko Reaction: Mechanism & Ester Synthesis | Chemca
Organic Chemistry

Tishchenko Reaction: Ester Formation from Aldehydes

By Chemca Editorial Team Last Updated: January 2026 7 min read

The Tishchenko Reaction is an organic chemical reaction that involves the disproportionation of two molecules of an aldehyde (with or without $\alpha$-hydrogen) to form an Ester. It is essentially a modified Cannizzaro reaction carried out in the presence of an aluminium alkoxide catalyst.

1. General Reaction

Usually, two molecules of the same aldehyde react. One molecule is oxidized to a carboxylic acid, and the other is reduced to an alcohol. However, unlike the Cannizzaro reaction, these two fragments combine immediately to form an ester.

$$ 2R-CHO \xrightarrow{Al(OC_2H_5)_3} R-COO-CH_2-R $$

Conditions:

  • Substrate: Aldehydes (e.g., Acetaldehyde, Benzaldehyde).
  • Reagent: Aluminium Ethoxide ($Al(OEt)_3$) or Aluminium Isopropoxide.
  • Product: Ester.

2. Detailed Mechanism

The reaction proceeds via a concerted hydride transfer mechanism facilitated by the Lewis acidic Aluminium atom.

Step 1: Coordination

The carbonyl oxygen of the aldehyde coordinates with the aluminium atom of the alkoxide catalyst, increasing the electrophilicity of the carbonyl carbon.

Step 2: Nucleophilic Addition

A second molecule of aldehyde adds to the complex, leading to a hemiacetal-like intermediate coordinated to the aluminium.

Step 3: Hydride Transfer (Key Step)

An intramolecular 1,3-Hydride Shift occurs. A hydride moves from the carbon of the "alcohol-to-be" part to the carbonyl carbon of the "acid-to-be" part. This regenerates the carbonyl bond in one fragment (forming the acyl part) and creates an alkoxide in the other.

The transition state involves a cyclic structure where Aluminium holds both reacting aldehyde molecules close together to facilitate the hydride transfer.

Step 4: Product Release

The ester is released, and the catalyst is regenerated.

3. Examples

A. Synthesis of Ethyl Acetate

Reaction of two molecules of Acetaldehyde ($CH_3CHO$).

$$ 2CH_3CHO \xrightarrow{Al(OEt)_3} \underbrace{CH_3COOCH_2CH_3}_{\text{Ethyl Acetate}} $$

B. Synthesis of Benzyl Benzoate

Reaction of two molecules of Benzaldehyde ($C_6H_5CHO$).

$$ 2C_6H_5CHO \xrightarrow{Al(OEt)_3} \underbrace{C_6H_5COOCH_2C_6H_5}_{\text{Benzyl Benzoate}} $$

4. Comparison with Cannizzaro

Key Differences

  • Substrate Scope: Cannizzaro is strictly for aldehydes without $\alpha$-hydrogens. Tishchenko works for all aldehydes (even those with $\alpha$-H like Acetaldehyde).
  • Product: Cannizzaro gives Salt of Acid + Alcohol (separate). Tishchenko gives an Ester (combined).
  • Reagent: Cannizzaro uses strong base ($NaOH$). Tishchenko uses Aluminium Alkoxide ($Al(OR)_3$).

5. Intramolecular Tishchenko

If the reaction is carried out on a dialdehyde, it leads to the formation of cyclic esters known as Lactones.

Tishchenko Reaction Quiz

Test your concepts on Ester formation. 10 MCQs with explanations.

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