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Reformatsky Reaction: Mechanism & Beta-Hydroxy Esters | Chemca

Reformatsky Reaction: Mechanism & Beta-Hydroxy Esters | Chemca
Organic Chemistry

Reformatsky Reaction: Synthesis of $\beta$-Hydroxy Esters

By Chemca Editorial Team Last Updated: January 2026 8 min read

The Reformatsky Reaction involves the condensation of an $\alpha$-halo ester (usually $\alpha$-bromo ester) with a carbonyl compound (aldehyde or ketone) in the presence of Zinc metal. The product obtained after acid hydrolysis is a $\beta$-hydroxy ester.

1. General Reaction

Zinc reacts with the $\alpha$-halo ester to form an organozinc reagent, which then attacks the ketone/aldehyde.

$$ R-CHO + Br-CH_2-COOEt \xrightarrow{1. \ Zn, \ Benzene} \xrightarrow{2. \ H_3O^+} R-CH(OH)-CH_2-COOEt $$

Key Components:

  • Carbonyl Source: Aldehyde or Ketone.
  • Nucleophile Source: $\alpha$-Halo ester (e.g., Ethyl bromoacetate).
  • Metal: Zinc dust ($Zn$).
  • Solvent: Inert solvents like Benzene, Ether, or THF.

2. Detailed Mechanism

The mechanism is analogous to the Grignard reaction but uses Zinc instead of Magnesium.

Step 1: Formation of Reformatsky Reagent

Zinc inserts into the Carbon-Bromine bond to form an organozinc bromide (Reformatsky Reagent). This exists as a Zinc Enolate.

$$ Br-CH_2-COOEt + Zn \rightarrow Br-Zn-CH_2-COOEt $$

(Resonance stabilized Zinc Enolate)

Step 2: Nucleophilic Attack

The organozinc reagent (acting as a nucleophile) attacks the electrophilic carbonyl carbon of the aldehyde/ketone.

$$ R-CHO + BrZn-CH_2-COOEt \rightarrow R-CH(OZnBr)-CH_2-COOEt $$

Step 3: Acid Hydrolysis

Dilute acid is added to hydrolyze the zinc alkoxide intermediate into the final alcohol.

$$ R-CH(OZnBr)-CH_2-COOEt + H_3O^+ \rightarrow R-CH(OH)-CH_2-COOEt + Zn(OH)Br $$

3. Why Zinc and not Magnesium? (Chemoselectivity)

Crucial Concept

Magnesium (Grignard Reagent) is highly reactive and would react with the ester group of the $\alpha$-halo ester molecule itself (Self-reaction/Polymerization).

Zinc (Reformatsky Reagent) is less electropositive and less reactive. The C-Zn bond is less polar than the C-Mg bond. Therefore, the organozinc reagent is reactive enough to attack aldehydes/ketones but inert towards the ester group.

4. Applications and Variations

Synthesis of $\alpha,\beta$-Unsaturated Esters

The $\beta$-hydroxy ester product can be easily dehydrated using acid and heat to form $\alpha,\beta$-unsaturated esters.

$$ R-CH(OH)-CH_2-COOEt \xrightarrow{H^+, \ \Delta} R-CH=CH-COOEt $$

Example: Benzaldehyde + Ethyl Bromoacetate

Forms Ethyl 3-hydroxy-3-phenylpropanoate.

5. Summary vs Grignard

Feature Grignard Reaction Reformatsky Reaction
Metal Magnesium ($Mg$) Zinc ($Zn$)
Reactivity Very High (Reacts with esters) Moderate (Tolerates esters)
Halide Type Alkyl Halide $\alpha$-Halo Ester

Reformatsky Quiz

Test your concepts on Organozinc chemistry. 10 MCQs with explanations.

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