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Mistake Bank: P-Block (Gr 15-18) | Chemca

Mistake Bank: P-Block (Gr 15-18) | ChemCa

The Mistake Bank

P-Block Elements (Groups 15, 16, 17, 18)

From Nitrogen's bonding to Xenon's reactions—handle with care.

Nitrogen Pentahalide ($NCl_5$)

Group 15 - Valency

Scenario: Why does $PCl_5$ exist but $NCl_5$ does not?

What Students Do

Student thinks: "Nitrogen is too small to hold 5 chlorines."

Or: "Nitrogen is not electronegative enough."

(Size is a factor, but not the primary reason for valency limit.)

The Correct Way

Absence of d-orbitals!

Nitrogen is in the 2nd period ($2s^2 2p^3$). It has NO 2d orbitals.

It cannot expand its covalency beyond 4 (using one 2s and three 2p).

Phosphorus ($3s, 3p, 3d$) can expand its octet.

Bond Strength: $F_2$ vs $Cl_2$

Group 17 - Halogens

Scenario: Which bond is stronger: $F-F$ or $Cl-Cl$?

What Students Do

Student applies size trend: "Smaller bond length = Stronger bond."

Answer: "$F-F$ is stronger."

(The Fluorine Anomaly strikes!)

The Correct Way

Electron-Electron Repulsion!

Fluorine is so small that the lone pairs on the two F atoms repel each other strongly.

This repulsion weakens the bond significantly.

Order: $Cl-Cl > Br-Br > F-F > I-I$.

Boiling Points of Hydrides

Group 16 - Trends

Scenario: Arrange Boiling Points: $H_2O, H_2S, H_2Se, H_2Te$.

What Students Do

Student follows molecular mass trend purely.

$$ H_2O < H_2S < H_2Se < H_2Te $$

(Water is liquid, Hydrogen Sulfide is gas!)

The Correct Way

Hydrogen Bonding Anomaly!

Water forms strong intermolecular H-bonds, making its BP exceptionally high.

For the rest, BP increases with mass (Van der Waals forces).

Correct Order: $H_2S < H_2Se < H_2Te < H_2O$.

Hydrolysis of Xenon Fluorides

Group 18 - Noble Gases

Scenario: Complete reaction: $XeF_4 + H_2O \rightarrow$ ?

What Students Do

Student assumes simple substitution like $XeF_6$.

$$ XeF_4 + H_2O \rightarrow XeO_2 + HF $$

(Incomplete!)

The Correct Way

Disproportionation!

$XeF_4$ hydrolysis is a redox reaction.

Xenon goes to both $Xe$ (0) and $XeO_3$ (+6).

$$ 6XeF_4 + 12H_2O \rightarrow 4Xe + 2XeO_3 + 24HF + 3O_2 $$

Acidity of Oxoacids

Group 17 - Acidity

Scenario: Which is more acidic? $HClO$ or $HClO_4$?

What Students Do

Student gets confused between oxidizing power and acidity.

Thinks: "$HClO$ is a strong oxidizer, so maybe it's a strong acid?"

The Correct Way

Oxidation Number Rule!

Higher Oxidation State of Central Atom = More Acidic.

$HClO_4$ ($Cl=+7$) is one of the strongest acids known.

$HClO$ ($Cl=+1$) is very weak.

Order: $HClO < HClO_2 < HClO_3 < HClO_4$.

Reaction of $Cl_2$ with Ammonia

Group 17 - Reactions

Scenario: Product of $NH_3 (\text{Excess}) + Cl_2$.

What Students Do

Student writes the explosive product: $NCl_3$.

(That happens when $Cl_2$ is in excess!)

The Correct Way

Ammonium Chloride!

If Ammonia is in excess, it acts as a base to neutralize the acid formed.

$$ 8NH_3 + 3Cl_2 \rightarrow 6NH_4Cl + N_2 $$

Product: $NH_4Cl + N_2$.

Confess Your Sins!

"P-Block reactions are all about conditions. Excess, dilute, hot, cold... did you miss a keyword?"

Did one of these catch you? Or do you have a different horror story from your last exam?

Scroll down to the comments section below and tell us:

"Which mistake were you making?"

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