Search This Blog

Translate

Gattermann-Koch Reaction: Mechanism & Formylation | Chemca

Gattermann-Koch Reaction: Mechanism & Formylation | Chemca
Organic Chemistry

Gattermann-Koch Reaction: Synthesis of Benzaldehyde

By Chemca Editorial Team Last Updated: January 2026 7 min read

The Gattermann-Koch Reaction is an industrial method for the formylation of benzene and alkylbenzenes. It involves treating the aromatic compound with Carbon Monoxide ($CO$) and Hydrogen Chloride ($HCl$) in the presence of a Lewis acid catalyst ($AlCl_3$) and a trace of Copper(I) Chloride ($CuCl$) to produce Benzaldehyde or substituted benzaldehydes.

1. General Reaction

Benzene reacts with a mixture of CO and HCl to introduce a formyl group ($-CHO$) onto the ring.

$$ C_6H_6 + CO + HCl \xrightarrow{Anhyd. \ AlCl_3 / CuCl} \underbrace{C_6H_5CHO}_{\text{Benzaldehyde}} + HCl $$

Conditions:

  • Reagents: Carbon Monoxide ($CO$) + Dry $HCl$ gas.
  • Catalyst: Anhydrous Aluminium Chloride ($AlCl_3$).
  • Co-Catalyst: Cuprous Chloride ($CuCl$) is essential (assists reaction with CO).
  • Product: Aromatic Aldehyde.

2. Detailed Mechanism

The reaction is an example of Electrophilic Aromatic Substitution (EAS). The attacking electrophile is the Formyl Cation ($H-C^+=O$).

Step 1: Generation of Electrophile

Technically, Formyl Chloride ($HCOCl$) is unstable at room temperature. The reagents $CO$ and $HCl$ react in the presence of the catalyst to generate the active electrophile in situ.

$$ CO + HCl \rightleftharpoons [HCOCl] $$ $$ [HCOCl] + AlCl_3 \rightarrow [H-C^+=O \leftrightarrow H-C \equiv O^+] + [AlCl_4]^- $$

Note: CuCl helps in absorbing Carbon Monoxide and facilitating its reaction.

Step 2: Electrophilic Attack

The Formyl cation attacks the electron-rich benzene ring to form a sigma complex (Wheland intermediate).

$$ C_6H_6 + HCO^+ \rightarrow [C_6H_6-CHO]^+ $$

Step 3: Deprotonation

The base ($[AlCl_4]^-$) abstracts a proton from the intermediate to restore aromaticity, yielding Benzaldehyde and regenerating the catalyst.

$$ [C_6H_6-CHO]^+ + [AlCl_4]^- \rightarrow C_6H_5CHO + HCl + AlCl_3 $$

3. Comparison: Gattermann vs. Gattermann-Koch

Don't Confuse Them!

  • Gattermann-Koch: Uses CO + HCl. Product is Benzaldehyde. Catalyst needs $CuCl$.
  • Gattermann Reaction: Uses HCN + HCl (Hydrogen Cyanide). Intermediate is an Aldimine ($Ar-CH=NH$), which is hydrolyzed to Benzaldehyde.

4. Limitations

  • Not for Phenols/Anilines: This reaction is typically not applicable to Phenol or Aniline. The Lewis acid ($AlCl_3$) coordinates strongly with the lone pairs on Oxygen or Nitrogen, deactivating the ring or forming stable complexes that prevent reaction. (Gattermann reaction using HCN is preferred for phenols).
  • Alkylbenzenes: For Toluene, the major product is p-Tolualdehyde due to steric hindrance at the ortho position.

5. Summary Table

Feature Reaction Detail
Substrate Benzene, Alkylbenzenes
Reagents $CO, HCl$
Catalyst $AlCl_3 + CuCl$
Electrophile Formyl Cation ($HCO^+$)

Gattermann-Koch Quiz

Test your concepts on Formylation. 10 MCQs with explanations.

No comments:

Post a Comment

JEE Main and Advanced 2026 – Complete Guide, Syllabus, Exam Dates, and Strategy

  JEE Main and Advanced 2026 – Complete Guide, Syllabus, Exam Dates, and Strategy JEE Main and Advanced 2026 are two of the most...

Popular Posts