Empirical & Molecular Formula
Essential Chemistry Notes & Practice for JEE (Main/Advanced) & NEET
1. Definitions
Empirical Formula (EF): Represents the simplest whole-number ratio of various atoms present in a compound. (e.g., Glucose $CH_2O$).
Molecular Formula (MF): Represents the actual number of atoms of various elements present in one molecule of the compound. (e.g., Glucose $C_6H_{12}O_6$).
2. Relationship between Empirical & Molecular Formula
The Molecular Formula is a simple whole-number multiple of the Empirical Formula.
Where $n$ is a positive integer (1, 2, 3...) calculated as:
$$ n = \frac{\text{Molecular Mass}}{\text{Empirical Formula Mass}} $$Note: If Vapour Density (VD) is given, remember that $\text{Molecular Mass} = 2 \times VD$.
3. Steps to Determine Empirical Formula
When given the percentage composition of elements by mass:
- Step 1: Assume a 100g sample. The percentage becomes mass in grams.
- Step 2: Calculate moles of each element ($ \text{Moles} = \frac{\text{Mass}}{\text{Atomic Mass}} $).
- Step 3: Divide all mole values by the smallest mole value obtained to get the simplest ratio.
- Step 4: If ratios are not whole numbers (e.g., 1.5), multiply all by a suitable integer (e.g., 2) to convert them to whole numbers.
Example:
A compound contains 80% Carbon and 20% Hydrogen.
| Element | % Mass | Atomic Mass | Relative Moles | Simplest Ratio |
|---|---|---|---|---|
| C | 80 | 12 | $80/12 = 6.66$ | $6.66/6.66 = 1$ |
| H | 20 | 1 | $20/1 = 20$ | $20/6.66 \approx 3$ |
Empirical Formula: $CH_3$
Test Your Concepts
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