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DIBAL-H: Selective Reduction to Aldehydes | Chemca

DIBAL-H: Selective Reduction to Aldehydes | Chemca
Organic Chemistry

DIBAL-H: The Selective Reducing Agent

By Chemca Editorial Team Last Updated: January 2026 8 min read

DIBAL-H (Diisobutylaluminium hydride) is a specialized reducing agent widely used in organic synthesis. Unlike strong reducing agents like $LiAlH_4$, DIBAL-H is electrophilic and can perform partial reductions, specifically converting Esters and Nitriles directly into Aldehydes under controlled low-temperature conditions.

1. Structure and Properties

DIBAL-H is an organoaluminium compound existing as a dimer or trimer.
Formula: $[(CH_3)_2CHCH_2]_2AlH$ or $(i-Bu)_2AlH$.

$$ R = -CH_2-CH(CH_3)_2 \quad (\text{Isobutyl}) $$
  • It acts as a Lewis Acid due to the vacant p-orbital on Aluminum.
  • It is typically used in non-polar solvents like Toluene, Hexane, or DCM.
  • It is pyrophoric and reacts violently with air/water.

2. Reduction of Esters to Aldehydes

The most famous application of DIBAL-H is the partial reduction of esters to aldehydes. This reaction must be carried out at very low temperatures ($-78^\circ C$).

$$ R-COOR' \xrightarrow{1. \ DIBAL-H, \ -78^\circ C} \xrightarrow{2. \ H_2O} R-CHO + R'OH $$

Mechanism (Why it stops at Aldehyde)

  1. Complexation: The carbonyl oxygen donates electron density to the electrophilic Aluminum atom.
  2. Hydride Transfer: A hydride ion ($H^-$) is transferred from Al to the carbonyl carbon, forming a stable Tetrahedral Intermediate.
  3. Stability at Low Temp: At $-78^\circ C$, this aluminum-alkoxide intermediate is stable and does not collapse to eliminate the alkoxide group (which would form an aldehyde that could be further reduced).
  4. Hydrolysis: Upon adding water (quenching), the intermediate breaks down to release the Aldehyde.

Temperature is Key!

If the reaction is performed at room temperature, the intermediate collapses, and DIBAL-H (if in excess) will reduce the aldehyde further to a Primary Alcohol.

3. Reduction of Nitriles to Aldehydes

DIBAL-H reduces nitriles ($R-CN$) to Imines, which upon hydrolysis yield Aldehydes.

$$ R-C \equiv N \xrightarrow{1. \ DIBAL-H} \underbrace{R-CH=NH}_{\text{Imine}} \xrightarrow{2. \ H_3O^+} R-CHO $$

4. Reduction of Lactones to Lactols

Cyclic esters (Lactones) are reduced to cyclic hemiacetals (Lactols).

Lactone $\xrightarrow{1. \ DIBAL-H, \ -78^\circ C}$ Lactol (Cyclic Hemiacetal)

Lactols are useful because they are equivalent to hydroxy-aldehydes.

5. Comparison of Reducing Agents

Substrate Product with $LiAlH_4$ Product with $NaBH_4$ Product with DIBAL-H ($-78^\circ C$)
Ester ($RCOOR'$) Alcohol ($RCH_2OH$) No Reaction Aldehyde ($RCHO$)
Nitrile ($RCN$) Amine ($RCH_2NH_2$) No Reaction Aldehyde ($RCHO$)
Alkene ($C=C$) No Reaction No Reaction No Reaction

6. Chemoselectivity

DIBAL-H does not reduce carbon-carbon double ($C=C$) or triple ($C \equiv C$) bonds within the molecule (unless conjugated to the carbonyl, but even then, conditions can be tuned). This allows selective reduction of the ester group in unsaturated esters.

Example: $CH_3-CH=CH-COOEt \xrightarrow{DIBAL-H} CH_3-CH=CH-CHO$

DIBAL-H Quiz

Test your concepts on Selective Reduction. 10 MCQs with explanations.

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