Coordination Compounds
NCERT Class 12 Chemistry • Complete Study Guide & Practice Quiz
Class 12
JEE / NEET
List of Important Ligands
| Ligand Formula | Common Name | IUPAC Name | Coordination Type | Denticity |
|---|---|---|---|---|
| NH₃ | Ammonia | Ammine | Neutral ligand | Monodentate |
| H₂O | Water | Aqua | Neutral ligand | Monodentate |
| Cl⁻ | Chloride ion | Chloro | Anionic ligand | Monodentate |
| OH⁻ | Hydroxide ion | Hydroxo | Anionic ligand | Monodentate |
| CN⁻ | Cyanide ion | Cyano | Anionic ligand | Monodentate |
| NO₂⁻ (via N) | Nitrito (N-bound) | Nitrito-N | Anionic ligand | Monodentate |
| NO₂⁻ (via O) | Nitrito (O-bound) | Nitrito-O | Anionic ligand | Monodentate |
| SCN⁻ (via S) | Thiocyanato (S-bound) | Thiocyanato-S | Anionic ligand | Monodentate |
| SCN⁻ (via N) | Thiocyanato (N-bound) | Thiocyanato-N | Anionic ligand | Monodentate |
| CO | Carbonyl | Carbonyl | Neutral ligand | Monodentate |
| C₂O₄²⁻ | Oxalate ion | Oxalato | Anionic ligand | Bidentate (chelating) |
| en | Ethylenediamine | Ethane-1,2-diamine | Neutral ligand | Bidentate (chelating) |
| EDTA⁴⁻ | Ethylenediaminetetraacetate | Ethane-1,2-diylbis(iminodiacetato) | Anionic ligand | Hexadentate (chelating) |
| NH₂CH₂COO⁻ | Glycinate ion | Aminoacetato | Anionic ligand | Bidentate |
| SO₄²⁻ | Sulfate ion | Sulfato | Anionic ligand | Usually bidentate |
| NO₃⁻ | Nitrate ion | Nitrato | Anionic ligand | Monodentate / Bidentate |
| PPh₃ | Triphenylphosphine | Triphenylphosphane | Neutral ligand | Monodentate |
Comprehensive Study Guide Q&A
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Q: What is a coordination compound?A: A compound containing a central metal atom/ion bonded to ligands via coordinate bonds.
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Q: What is a ligand?A: An ion or molecule that donates a lone pair of electrons to the central metal atom/ion.
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Q: What is coordination number?A: The number of ligand donor atoms directly bonded to the central metal ion.
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Q: What are monodentate ligands?A: Ligands that donate only one pair of electrons (e.g., NH₃, H₂O, Cl⁻).
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Q: Give an example of a polydentate ligand.A: Ethylenediamine (en), Oxalate (C₂O₄²⁻).
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Q: What is a chelating ligand?A: A ligand that forms two or more coordinate bonds with the same central metal ion.
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Q: What is the oxidation number of Co in [Co(NH₃)₆]Cl₃?A: +3.
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Q: What is the difference between inner and outer orbital complexes?A: Inner orbital uses (n-1)d orbitals, outer orbital uses nd orbitals for hybridization.
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Q: What is EAN rule?A: Effective Atomic Number = Atomic number of metal + electrons donated by ligands – oxidation state.
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Q: Which law explains isomerism in coordination compounds?
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Q: What is the name of [Cr(H₂O)₆]Cl₃?
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Q: Write the formula of potassium ferrocyanide.A: K₄[Fe(CN)₆].
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Q: Name [Ni(CO)₄].A: Tetracarbonylnickel(0).
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Q: Give the name of [Pt(NH₃)₂Cl₂].A: Diamminedichloroplatinum(II).
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Q: Name [Cu(NH₃)₄]SO₄.
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Q: What type of isomerism is shown by [Co(NH₃)₅Cl]SO₄ and [Co(NH₃)₅SO₄]Cl?A: Ionization isomerism.
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Q: Name the isomerism in [Co(en)₃]Cl₃.
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Q: [Pt(NH₃)₂Cl₂] shows which type of isomerism?A: Geometrical isomerism (cis/trans).
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Q: What type of isomerism is shown when one ligand changes its point of attachment?
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Q: Give an example of coordination isomerism.A: [Co(NH₃)₆][Cr(CN)₆] and [Cr(NH₃)₆][Co(CN)₆].
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Q: Hybridization of Ni in [Ni(CN)₄]²⁻?A: dsp² (square planar).
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Q: Hybridization in [NiCl₄]²⁻?A: sp³ (tetrahedral).
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Q: What is the geometry of [Fe(CN)₆]³⁻?A: Octahedral.
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Q: Magnetic moment of [Ti(H₂O)₆]³⁺? (d¹ system)A: √1(1+2) = 1.73 BM.
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Q: Which has more unpaired electrons: [Fe(CN)₆]³⁻ or [FeF₆]³⁻?A: [FeF₆]³⁻ (weak ligand field).
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Q: What is crystal field splitting?A: Splitting of d-orbitals of a metal ion in presence of ligands.
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Q: Why is [Fe(CN)₆]⁴⁻ diamagnetic?A: CN⁻ is a strong field ligand causing pairing of electrons.
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Q: Why is [FeF₆]³⁻ paramagnetic?A: F⁻ is a weak field ligand, no pairing of electrons.
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Q: In octahedral field, d-orbitals split into which sets?A: t₂g (lower energy) and eg (higher energy).
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Q: Write the electronic configuration of Co³⁺ in [CoF₆]³⁻.A: t₂g⁴ eg² (high spin).
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Q: Why are transition metal complexes often colored?A: Due to d-d transitions absorbing visible light.
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Q: Why is [Ti(H₂O)₆]³⁺ purple?A: d-d transition in d¹ system absorbs green light.
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Q: Why is [Cu(H₂O)₆]²⁺ blue?A: Absorption of red light causes complementary blue color.
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Q: What is the magnetic nature of [Ni(CO)₄]?A: Diamagnetic (all electrons paired).
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Q: State the reason why [Mn(H₂O)₆]²⁺ is pale pink.A: Weak d-d transitions (d⁵ high spin).
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Q: Formula of EDTA?
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Q: Name one use of EDTA.A: Used in complexometric titrations for hardness of water.
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Q: What is cisplatin used for?A: Anti-cancer drug.
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Q: Name the active species in Vitamin B₁₂.A: Co(III) coordination complex.
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Q: Which coordination compound is known as Prussian Blue?A: Fe₄[Fe(CN)₆]₃.
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Q: Define stability constant.A: Equilibrium constant for the formation of a complex.
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Q: Between [Fe(CN)₆]³⁻ and [FeCl₆]³⁻, which is more stable?A: [Fe(CN)₆]³⁻ (due to strong field ligand CN⁻).
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Q: Which follows chelate effect: EDTA or NH₃?A: EDTA.
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Q: Write IUPAC name of [Fe(H₂O)₅NO]SO₄.A: Pentaaquanitrosyliron(II) sulfate.
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Q: What is the charge on [MnO₄]⁻?A: –1.
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Q: Why are low spin complexes more stable than high spin sometimes?A: Higher crystal field stabilization energy (CFSE).
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Q: Which complex is low spin: [Fe(CN)₆]³⁻ or [Fe(H₂O)₆]³⁺?A: [Fe(CN)₆]³⁻.
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Q: What is the coordination number in [Cr(C₂O₄)₃]³⁻?A: 6 (oxalate is bidentate).
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Q: Write geometry of [Cu(NH₃)₄]²⁺.A: Square planar or distorted tetrahedral.
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Q: Which rule helps predict absorbance in coordination compounds?A: Selection rules (Laporte and spin selection rules).
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Q: Why does [Ni(CN)₄]²⁻ have square planar geometry while [NiCl₄]²⁻ has tetrahedral geometry?A: CN⁻ is a strong field ligand (dsp² hybridization), while Cl⁻ is weak field (sp³ hybridization).
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Q: Which complex is diamagnetic: [CoF₆]³⁻ or [Co(NH₃)₆]³⁺?A: [Co(NH₃)₆]³⁺, because NH₃ induces pairing (low spin).
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Q: Why does [Ti(H₂O)₆]³⁺ show color, but [Sc(H₂O)₆]³⁺ is colorless?A: Ti³⁺ has d¹ electron (d-d transition possible), Sc³⁺ is d⁰ (no d-d transition).
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Q: Between [Fe(CN)₆]³⁻ and [Fe(CN)₆]⁴⁻, which one is more stable and why?A: [Fe(CN)₆]³⁻ is more stable due to stronger CFSE of d⁵ low spin.
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Q: Why is tetraamminecopper(II) sulfate solution blue?A: It absorbs orange-red light due to d-d transitions, reflecting blue.
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Q: Can a tetrahedral complex show geometrical isomerism?A: No, only square planar and octahedral complexes show it.
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Q: Which complex shows optical isomerism: [Co(en)₃]³⁺ or [Co(NH₃)₆]³⁺?A: [Co(en)₃]³⁺ (chiral due to bidentate ligands).
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Q: Why does [PtCl₂(NH₃)₂] have two isomers but [NiCl₄]²⁻ does not?A: Square planar geometry of Pt complex allows cis/trans; Ni complex is tetrahedral.
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Q: Which type of isomerism is shown by [Co(NO₂)(NH₃)₅]Cl₂ and [Co(ONO)(NH₃)₅]Cl₂?A: Linkage isomerism (NO₂⁻ vs ONO⁻).
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Q: Differentiate coordination and ionization isomers with one example.A: [Cu(NH₃)₄][PtCl₄] vs [Pt(NH₃)₄][CuCl₄]; [Co(NH₃)₅Br]SO₄ vs [Co(NH₃)₅SO₄]Br.
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Q: Why are d⁰ and d¹⁰ complexes usually colorless?A: No d-d transitions possible.
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Q: Arrange [Ti(H₂O)₆]³⁺, [V(H₂O)₆]³⁺, [Cr(H₂O)₆]³⁺ in increasing CFSE.A: Ti³⁺ < V³⁺ < Cr³⁺ (increasing d-electrons).
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Q: Why is [Fe(H₂O)₆]²⁺ strongly paramagnetic, but [Fe(CN)₆]⁴⁻ is diamagnetic?A: H₂O is weak ligand (high spin d⁶), CN⁻ is strong ligand (low spin d⁶).
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Q: Explain Jahn–Teller distortion in [Cu(H₂O)₆]²⁺.A: Unequal occupancy of eg orbitals (d⁹ system) leads to elongation along z-axis.
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Q: Which is the stronger ligand, en or NH₃?A: en, due to chelate effect and stronger field strength.
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Q: Between [Ag(NH₃)₂]⁺ and [Ag(CN)₂]⁻, which is more stable?A: [Ag(CN)₂]⁻ (cyanide forms very stable complexes).
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Q: Why is EDTA a better ligand than NH₃?A: It is hexadentate (chelating effect gives higher stability).
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Q: Why does [Fe(CO)₅] have strong metal-ligand bonds?A: CO shows synergic bonding (ฯ donation + ฯ backbonding).
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Q: Why is [Cr(NH₃)₆]³⁺ violet, but [Cr(H₂O)₆]³⁺ green?A: Different ligand field strengths cause different absorption frequencies.
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Q: Which is thermodynamically more stable: [Co(en)₃]³⁺ or [Co(NH₃)₆]³⁺?A: [Co(en)₃]³⁺ due to chelation.
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Q: Why does [Zn(NH₃)₄]²⁺ not show color?A: Zn²⁺ is d¹⁰, no d-d transitions.
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Q: In [Mn(H₂O)₆]²⁺, why is CFSE = 0?A: High spin d⁵, equal filling of t₂g and eg
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Q: Why is [Fe(CN)₆]³⁻ less stable than [Fe(CN)₆]⁴⁻?A: Fe³⁺ has higher charge density than Fe²⁺, so faces more repulsion with 6 CN⁻ ligands.
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Q: Why do d-d transitions violate Laporte’s rule in [Ti(H₂O)₆]³⁺?A: Vibronic coupling relaxes selection rule.
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Q: Why is [Ni(CO)₄] diamagnetic despite Ni(0) being d⁸?A: Strong CO field causes pairing → dsp² hybridization, no unpaired e⁻.
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Q: Why is K₂[HgI₄] used in Nessler’s reagent?A: It detects NH₃ by forming a brown complex.
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Q: How does cisplatin act as an anticancer drug?A: It binds to DNA and prevents replication.
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Q: Why is EDTA used in water softening?A: It binds strongly to Ca²⁺ and Mg²⁺ ions.
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Q: Which coordination compound is used in photography fixing?A: Sodium thiosulfate (Na₂S₂O₃).
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Q: What gives the deep blue color in the Cu²⁺–NH₃ complex test?A: Formation of [Cu(NH₃)₄]²⁺.
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Q: Which complex shows both linkage and geometrical isomerism?A: [Co(NO₂)₂(NH₃)₄]⁺.
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Q: Out of [Fe(H₂O)₆]²⁺ and [Fe(H₂O)₆]³⁺, which is more easily oxidized?A: Fe²⁺ → Fe³⁺, because Fe³⁺ is more stable in water.
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Q: Write CFSE expression for high spin octahedral complexes.A: CFSE = –0.4xฮ₀ + 0.6yฮ₀, where x = no. of e⁻ in t₂g, y = e⁻ in eg.
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Q: Which shows greater magnetic moment: [CoF₆]³⁻ or [Co(NH₃)₆]³⁺?A: [CoF₆]³⁻ (weak field, high spin, more unpaired e⁻).
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Q: Why is [Cr(en)₃]³⁺ optically active?A: It exists as two enantiomers (d and l forms).
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Q: Calculate CFSE of [Fe(CN)₆]⁴⁻. (Fe²⁺, d⁶, low spin)A: CFSE = (–0.4×6ฮ₀) = –2.4ฮ₀ + pairing energy.
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Q: Spin only magnetic moment of [MnF₆]³⁻ (d⁴ high spin)?A: √4(4+2) = √24 = 4.9 BM.
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Q: Why does NH₃ act as a ligand but not CH₄?A: NH₃ has a lone pair on N, CH₄ has no lone pairs.
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Q: In [Cr(H₂O)₆]³⁺, what is the color?A: Violet-green (depends on light) due to d³ transitions.
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Q: Which is stronger ligand according to spectrochemical series: H₂O or NH₃?A: NH₃.
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Q: Why does Co²⁺ prefer tetrahedral complexes while Co³⁺ prefers octahedral?A: Higher charge stabilizes more coordination.
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Q: What is the CFSE of d³ octahedral high spin complex?A: –1.2ฮ₀.
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Q: In [Ni(CN)₄]²⁻, why is Ni²⁺ using inner d-orbitals?A: Strong field CN⁻ causes pairing into 3d.
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Q: Is [Cu(NH₃)₄]²⁺ square planar or tetrahedral?A: Distorted square planar (Jahn–Teller distortion).
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Q: Why is NO considered an ambidentate ligand?A: It can bind via N or O atom.
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Q: Can [Zn(NH₃)₄]²⁺ be isostructural with [Cu(NH₃)₄]²⁺?A: No, Zn²⁺ complex is perfect tetrahedral; Cu²⁺ shows distortion.
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Q: Which has higher CFSE: strong field low spin or weak field high spin complexes?A: Strong field low spin.
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Q: Why do tetrahedral complexes rarely show low spin?A: Splitting energy (ฮt) is too small to cause pairing.
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Q: Why does [Fe(CO)₅] show synergic bonding but [Fe(H₂O)₆]²⁺ does not?A: H₂O cannot accept back-donation, CO can.
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Q: Which complex has greater stability: [Cu(NH₃)₄]²⁺ or [Cu(H₂O)₄]²⁺?A: [Cu(NH₃)₄]²⁺ (ligand field stabilization+stronger donor ability).
Basic Concepts
Nomenclature
Isomerism
Hybridization and Structures
Crystal Field Theory
Color, Spectra, and Properties
Important Compounds and Uses
Advanced and Conceptual
Structural and Conceptual
Further Isomerism
Further Crystal Field Theory
Stability and Reactions
Conceptual Traps
Further Applications
Advanced/Competitive Edge
Quantitative and CFSE Tricks
Edge Case Problems
Miscellaneous Challenge
Coordination Compounds Full Revision Quiz (50 MCQs)
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Thankyou so much sir ,,you are very hardworking,,and always there for your students ❤️
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