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Phosphorus Pentachloride (PCl5): Structure, Solid State & Hydrolysis

Phosphorus Pentachloride (PCl5): Structure, Solid State & Hydrolysis | chemca
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Inorganic Chemistry • Group 15 Halides

Phosphorus Pentachloride ($PCl_5$)

The $sp^3d$ Geometry, Ionic Solid State Anomaly, and Hydrolysis Reactions.

By chemca Team • Updated Sep 2026

Unlike Nitrogen, which is restricted to a maximum covalency of 4, Phosphorus possesses vacant 3d-orbitals. By promoting a 3s electron into the 3d subshell, Phosphorus can expand its octet to form five covalent bonds, leading to the creation of Phosphorus Pentachloride ($PCl_5$). It is a yellowish-white powder, fiercely reactive with water, and harbors a massive structural secret when in the solid state.

1. Preparation of $PCl_5$

A. Action of Chlorine on $PCl_3$

$PCl_5$ is easily prepared by passing an excess of dry chlorine gas through liquid phosphorus trichloride ($PCl_3$).

$PCl_3 + Cl_2 \rightarrow PCl_5$

B. Direct Chlorination of White Phosphorus

Alternatively, it is obtained by the action of an excess of dry chlorine on white phosphorus. (Recall that a limited supply of chlorine yields $PCl_3$).

$P_4 + 10Cl_2 \rightarrow 4PCl_5$

2. The Structural Anomaly: Gas vs. Solid Phase

This is arguably the most frequently tested concept regarding $PCl_5$ in competitive exams. The molecule completely changes its bonding nature depending on its physical state.

In Gas & Liquid Phase

In gaseous and liquid states, $PCl_5$ exists as a discrete, neutral covalent molecule with $sp^3d$ hybridization.

  • Geometry: Trigonal Bipyramidal (TBP).
  • Bond Angles: Three equatorial bonds at $120^\circ$, and two axial bonds at $90^\circ$ to the equatorial plane.
  • Crucial Fact: The two axial P-Cl bonds are longer and weaker than the three equatorial bonds. This is because the axial bond pairs suffer greater repulsion from the three equatorial bond pairs.
In the Solid State

In the solid state, $PCl_5$ completely abandons its covalent nature and exists as an ionic solid!

$[PCl_4]^+ [PCl_6]^-$
  • The Cation $[PCl_4]^+$ is Tetrahedral ($sp^3$ hybridized).
  • The Anion $[PCl_6]^-$ is Octahedral ($sp^3d^2$ hybridized).
  • Because it is an ionic compound in the solid state, it can conduct electricity when fused (melted).
Structural Transformation of PCl₅ Gas / Liquid Phase P Trigonal Bipyramidal (sp³d) Axial bonds longer (240 pm) Solid Phase (Ionic) P + [PCl₄]⁺ (Tetrahedral) P - [PCl₆]⁻ (Octahedral)

Figure 1: To relieve the strain of the axial bonds, $PCl_5$ disproportionates in the solid state into stable tetrahedral and octahedral ions.

3. Chemical Properties & Key Reactions

A. Action of Heat (Sublimation & Decomposition)

When heated, $PCl_5$ sublimes. Upon stronger heating, it decomposes into phosphorus trichloride and chlorine gas. The weakness of the two axial bonds is the exact reason it decomposes so readily.

$PCl_5 \xrightarrow{\Delta} PCl_3 + Cl_2 \uparrow$

B. Hydrolysis (Partial vs. Complete)

Like $PCl_3$, it reacts violently with water. However, the reaction occurs in two distinct steps depending on the amount of water available.

1. Partial Hydrolysis (Limited Water):

It first forms Phosphorus oxychloride ($POCl_3$).

$PCl_5 + H_2O \rightarrow \mathbf{POCl_3} + 2HCl$
2. Complete Hydrolysis (Excess Water):

With excess water, the $POCl_3$ reacts further to yield Orthophosphoric acid ($H_3PO_4$).

$POCl_3 + 3H_2O \rightarrow \mathbf{H_3PO_4} + 3HCl$

Overall Reaction: $PCl_5 + 4H_2O \rightarrow \mathbf{H_3PO_4} + 5HCl$

C. As a Powerful Chlorinating Agent

$PCl_5$ reacts vigorously with organic compounds containing -OH groups, converting them into chloro-derivatives.

⚠️ EXAM DIFFERENCE: When $PCl_3$ reacts with alcohols, the byproduct is $H_3PO_3$. But when $PCl_5$ reacts, the byproduct is always $POCl_3 + HCl$.
With Alcohols:
$C_2H_5OH + PCl_5 \rightarrow \mathbf{C_2H_5Cl} + POCl_3 + HCl$
(Ethanol $\rightarrow$ Ethyl Chloride)
With Carboxylic Acids:
$CH_3COOH + PCl_5 \rightarrow \mathbf{CH_3COCl} + POCl_3 + HCl$
(Acetic acid $\rightarrow$ Acetyl chloride)

D. Action on Finely Divided Metals

When heated with finely divided metals, $PCl_5$ acts as a chlorinating agent, forming metal chlorides and getting reduced to $PCl_3$.

$2Ag + PCl_5 \xrightarrow{\Delta} 2AgCl + PCl_3$

$Sn + 2PCl_5 \xrightarrow{\Delta} SnCl_4 + 2PCl_3$

Mastery Check: Phosphorus Pentachloride

15 High-Yield Questions to test your JEE/NEET Preparation

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