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Group 17 Reactivity with Metals: Metal Halides

Group 17 Reactivity with Metals: Metal Halides | chemca
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Inorganic Chemistry • Group 17

Reactivity with Metals

Master the formation of Metal Halides and the application of Fajans' Rules.

By chemca Team • Updated Sep 2026

Halogens are the most electronegative elements on the periodic table, while metals are electropositive. This combination results in highly vigorous, spontaneous reactions. Halogens react with metals to form a massive class of compounds known as Metal Halides. Because halogens only need one electron to complete their octet, they consistently exhibit a -1 oxidation state when bonded to metals.

1. Formation and Reactivity Trend

All halogens react directly with metals. The reactivity of the halogens towards metals decreases down the group.

Reactivity Order: $F_2 > Cl_2 > Br_2 > I_2$
$Mg(s) + Br_2(l) \rightarrow MgBr_2(s)$
(Magnesium bromide: Mg is +2, Br is -1)

The Power of Fluorine: Because Fluorine is the most powerful oxidizing agent, it reacts with almost all metals. In fact, it often forces the metal to exhibit its highest possible oxidation state (e.g., Uranium hexafluoride, $UF_6$, and Bismuth pentafluoride, $BiF_5$).

2. Ionic vs Covalent Character (Fajans' Rules)

This is the most highly tested concept in this section. While we generally think of metal halides as purely ionic salts (like $NaCl$), many metal halides are actually highly covalent! The nature of the bond is determined by Fajans' Rules.

Rule 1: Oxidation State of the Metal

If a metal exhibits more than one oxidation state, the halide in the higher oxidation state will be more covalent than the one in the lower oxidation state.

Why? A highly charged metal cation (e.g., $+4$) is smaller and has a massive polarizing power. It strongly pulls the electron cloud of the halide ion toward itself, leading to covalent orbital overlap.

  • $SnCl_4$ is more covalent than $SnCl_2$.
  • $PbCl_4$ is more covalent than $PbCl_2$.
  • $SbCl_5$ is more covalent than $SbCl_3$.
Rule 2: Size of the Halide Ion

For a given metal, the covalent character increases as the size of the halide ion increases.

Why? A larger halide ion (like $I^-$) holds its outer electrons very loosely. It is highly polarizable, meaning its electron cloud is easily distorted by the metal cation to form a covalent bond.

Covalent Character Order:
$MI > MBr > MCl > MF$
  • $AlF_3$ is purely ionic, while $AlCl_3$ is predominantly covalent.
Fajans' Rules: The Effect of Metal Oxidation State SnCl₂ (Tin(II) Chloride) Oxidation State: +2 Sn²⁺ Cl⁻ Predominantly IONIC Low charge = Low polarizing power. Electron cloud remains spherical. (Solid at Room Temp) SnCl₄ (Tin(IV) Chloride) Oxidation State: +4 Sn⁴⁺ Cl⁻ Predominantly COVALENT High charge = Massive polarizing power. Electron cloud distorts into covalent overlap. (Volatile Liquid at Room Temp)

Figure 1: Visualizing the difference between $SnCl_2$ and $SnCl_4$. The highly charged $Sn^{4+}$ cation severely distorts the chloride ion, leading to covalent character.

Crucial Exam Connection: Physical State
The shift from ionic to covalent bonding completely changes the physical properties of the compound. Ionic compounds form giant rigid crystal lattices, making them solids with high melting points (e.g., $SnCl_2$ is a solid, melting at $246^\circ\text{C}$). Covalent compounds form discrete molecules held together only by weak van der Waals forces, making them gases or volatile liquids (e.g., $SnCl_4$ is a fuming liquid, melting at $-33^\circ\text{C}$).

Mastery Check: Metal Halides

15 High-Yield Questions to test your JEE/NEET Preparation

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