Valency and Chemical Formulas
Complete ICSE Class 9 Guide | chemca.in
1. Electronic Concept of Valency
According to the modern electronic theory, valency is determined by the number of electrons in the outermost shell (valence shell).
Octet Rule: Atoms tend to lose, gain, or share electrons to achieve a stable configuration of 8 electrons in their valence shell (or 2 for Helium).
- Electropositive Valency: Metals lose electrons to become positive ions (Cations). E.g., $Na \rightarrow Na^+ + e^-$.
- Electronegative Valency: Non-metals gain electrons to become negative ions (Anions). E.g., $Cl + e^- \rightarrow Cl^-$.
2. Variable Valency
Certain elements exhibit more than one valency due to the involvement of electrons from the penultimate shell (shell before the outermost).
| Element | Lower Valency (-ous) | Higher Valency (-ic) |
|---|---|---|
| Iron ($Fe$) | $+2$ (Ferrous) | $+3$ (Ferric) |
| Copper ($Cu$) | $+1$ (Cuprous) | $+2$ (Cupric) |
| Mercury ($Hg$) | $+1$ (Mercurous) | $+2$ (Mercuric) |
| Lead ($Pb$) | $+2$ (Plumbous) | $+4$ (Plumbic) |
| Tin ($Sn$) | $+2$ (Stannous) | $+4$ (Stannic) |
3. Comprehensive List of Radicals
Positive Radicals (Cations)
| Monovalent ($+1$) | Divalent ($+2$) | Trivalent ($+3$) |
|---|---|---|
| Ammonium ($NH_4^+$) | Calcium ($Ca^{2+}$) | Aluminum ($Al^{3+}$) |
| Potassium ($K^+$) | Magnesium ($Mg^{2+}$) | Ferric ($Fe^{3+}$) |
| Sodium ($Na^+$) | Zinc ($Zn^{2+}$) | Chromium ($Cr^{3+}$) |
Negative Radicals (Anions)
| Monovalent ($-1$) | Divalent ($-2$) | Trivalent ($-3$) |
|---|---|---|
| Chloride ($Cl^-$) | Sulphate ($SO_4^{2-}$) | Phosphate ($PO_4^{3-}$) |
| Nitrate ($NO_3^-$) | Carbonate ($CO_3^{2-}$) | Nitride ($N^{3-}$) |
| Hydroxide ($OH^-$) | Oxide ($O^{2-}$) | Phosphide ($P^{3-}$) |
| Bicarbonate ($HCO_3^-$) | Dichromate ($Cr_2O_7^{2-}$) | - |
4. Step-by-Step Formula Writing
To write the formula for Magnesium Phosphate:
- Identify Symbols: Magnesium is $Mg$, Phosphate is $PO_4$.
- Assign Valencies: $Mg$ is $2+$, $PO_4$ is $3-$.
- Criss-Cross: The 3 goes to $Mg$ and 2 goes to $PO_4$.
- Result: $Mg_3(PO_4)_2$.
Live classes starting on E Acad Sutra
ReplyDelete