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Solutions – Class 12 Chemistry NEET MCQs
Solutions – Class 12 Chemistry NEET Practice MCQs
The mole fraction of solute in a 1 molal aqueous solution is approximately:
(a) 0.018 (b) 0.035 (c) 0.0177 (d) 0.27
If 0.5 mol of solute is dissolved in 500 g of water, the molality is:
(a) 0.5 m (b) 1.0 m (c) 2.0 m (d) 0.25 m
Which of the following is a colligative property?
(a) Osmotic pressure (b) Surface tension (c) Viscosity (d) Refractive index
The vapour pressure of pure water at 25°C is 23.8 mm Hg. The vapour pressure of a solution containing 18 g of glucose (C₆H₁₂O₆) in 180 g of water will be:
(a) 23.04 mm Hg (b) 22.8 mm Hg (c) 23.5 mm Hg (d) 23.0 mm Hg
Relative lowering of vapour pressure is equal to:
(a) Mole fraction of solute (b) Mole fraction of solvent (c) Molality (d) Molarity
Raoult’s law is applicable to:
(a) Ideal solutions (b) Non-ideal solutions (c) Azeotropic mixtures (d) Strong electrolytes
The elevation in boiling point for 1 molal urea solution is 0.52°C. The boiling point of the solution is:
(a) 100.52°C (b) 99.48°C (c) 101°C (d) 100°C
The depression in freezing point of a 0.1 molal NaCl solution (assuming complete dissociation) is (Kf = 1.86 K kg mol⁻¹):
(a) 0.186°C (b) 0.372°C (c) 0.093°C (d) 0.279°C
The osmotic pressure of a 0.1 M glucose solution at 27°C is (R = 0.0821 L atm K⁻¹ mol⁻¹):
(a) 2.46 atm (b) 1.23 atm (c) 4.92 atm (d) 0.82 atm
Which of the following represents a hypertonic solution?
(a) Its osmotic pressure is higher than another solution (b) Its osmotic pressure is lower (c) Same osmotic pressure (d) None of these
The value of van’t Hoff factor (i) for Na₂SO₄ is:
(a) 2 (b) 3 (c) 1 (d) 4
Which of the following solutions will have the highest boiling point?
(a) 1 M glucose (b) 1 M NaCl (c) 1 M CaCl₂ (d) 1 M urea
The osmotic pressure of a 0.01 M NaCl solution at 27°C assuming complete dissociation is approximately:
(a) 0.24 atm (b) 0.48 atm (c) 0.12 atm (d) 1.0 atm
Which of the following pairs forms an ideal solution?
(a) Benzene and toluene (b) Acetone and chloroform (c) Ethanol and water (d) HCl and water
The molarity of 18 g of glucose (C₆H₁₂O₆) in 1 L of solution is:
(a) 0.5 M (b) 0.1 M (c) 0.05 M (d) 0.2 M
If 0.1 mol of BaCl₂ is dissolved in 1 L of water, the total number of ions in the solution will be:
(a) 0.1 mol (b) 0.2 mol (c) 0.3 mol (d) 0.4 mol
Which concentration term is temperature independent?
(a) Molarity (b) Normality (c) Molality (d) All
The vapour pressure of an ideal solution of two volatile liquids A and B is given by:
(a) PA = PA°xA (b) PB = PB°xB (c) P = PA°xA + PB°xB (d) P = PA°xA × PB°xB
For a non-volatile solute, the vapour pressure of the solution compared to pure solvent is:
(a) Higher (b) Lower (c) Equal (d) Unpredictable
The molar mass of a solute that produces a depression of 0.93°C in the freezing point of 100 g water (Kf = 1.86 K kg mol⁻¹) when 5 g is dissolved is:
(a) 10 g/mol (b) 50 g/mol (c) 100 g/mol (d) 186 g/mol
Answers and Explanations
(c) 0.0177 – Mole fraction ≈ 1/(55.5+1)
(b) 1.0 m – Molality = 0.5 mol / 0.5 kg
(a) Osmotic pressure – depends only on number of solute particles
(a) 23.04 mm Hg – P = P₀(1–xsolute)
(a) Equal to mole fraction of solute
(a) Ideal solutions – obey Raoult’s law
(a) 100.52°C – 100 + 0.52
(b) 0.372°C – ΔTf = i×Kf×m = 2×1.86×0.1
(a) 2.46 atm – π = C R T = 0.1×0.0821×300
(a) Osmotic pressure higher → hypertonic
(b) 3 – Na₂SO₄ → 2Na⁺ + SO₄²⁻
(c) 1 M CaCl₂ – highest i (3)
(b) 0.48 atm – π = iCRT = 2×0.01×0.0821×300
(a) Benzene and toluene – similar structure and forces
(b) 0.1 M – 18/180 = 0.1 mol
(c) 0.3 mol – BaCl₂ → Ba²⁺ + 2Cl⁻
(c) Molality – based on mass, not volume
(c) P = PA°xA + PB°xB
(b) Lower – solute reduces vapour pressure
(c) 100 g/mol – ΔTf = Kf×m → m = 0.5 mol/kg → molar mass = 5/0.05 = 100
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